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Question

Two plates with diameters 3.5 cm and 2.5 cm are kept one above the other. The larger plate is placed at the bottom. What is the total area of the larger plate in sq. cm. that is visible?

This question was previously asked in
RRB ALP/Technician 2018 CBT 2 Electronics Mechanic Question Paper (23-Jan-2019) (Shift 1)
The correct answer is
$1.5\pi$

Plate Dimensions and Visible Area

The question requires calculating the visible surface area of the bottom plate when a smaller plate is placed on top. This visible area is the total area of the larger plate minus the portion covered by the smaller plate.

Given Plate Measurements

  • Larger plate diameter: $d_1 = 3.5$ cm
  • Smaller plate diameter: $d_2 = 2.5$ cm

Calculate Plate Radii

Convert the diameters to radii using the formula $r = \frac{d}{2}$:

  • Larger plate radius: $r_1 = \frac{3.5 \text{ cm}}{2} = 1.75$ cm
  • Smaller plate radius: $r_2 = \frac{2.5 \text{ cm}}{2} = 1.25$ cm

Calculate Plate Areas

Use the area formula for a circle, $A = \pi r^2$, to find the area of each plate:

  • Area of the larger plate: $A_1 = \pi r_1^2 = \pi (1.75)^2 = \pi(3.0625)$ sq. cm.
  • Area of the smaller plate: $A_2 = \pi r_2^2 = \pi (1.25)^2 = \pi(1.5625)$ sq. cm.

Determine Visible Area of Larger Plate

Since the smaller plate covers part of the larger plate, the visible area is the difference between their areas:

Visible Area $= A_1 - A_2$

Visible Area $= \pi(3.0625) - \pi(1.5625)$

Visible Area $= \pi(3.0625 - 1.5625)$

Visible Area $= \pi(1.5)$

Visible Area $= 1.5\pi$ sq. cm.

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