To find the area of a square given its diagonal, we can use a direct formula derived from the Pythagorean theorem.
Let 's' be the side length of the square and 'd' be the diagonal length. In a square, the diagonal divides it into two right-angled isosceles triangles. Applying the Pythagorean theorem (\(a^2 + b^2 = c^2\)):
The area of the square (A) is \(s^2\). Substituting A into the equation:
Given the diagonal \(d = 4\) cm:
Therefore, the area of the square is 8 cm\(^2\).
What is the area of this parallelogram in sq.cm.? The measurements are in cms.

A regular hexagonal garden with each side measuring 14 metres is surrounded by a circular jogging track that has a radius of 21 metres from the centre of the hexagon. Find the sum of the perimeters of both shapes.
(Use $\pi = \frac{22}{7}$)
What is the area of this parallelogram in sq.cm.? The measurements are in cms.
