If the diameter of a circle increases by 15%, then what will be the percentage increase in its area?
32.25%
Let's break down this geometry problem step-by-step to understand how a percentage increase in the diameter of a circle affects its area.
The area of a circle is calculated using its radius. The diameter is simply twice the radius.
Substituting the relationship between radius and diameter into the area formula, we can also write the area in terms of diameter:
$A_1 = \pi \left(\frac{D_1}{2}\right)^2 = \pi \frac{D_1^2}{4}$
The question states that the diameter of the circle increases by 15%. Let the new diameter be $D_2$.
Now, let's find the new radius, $r_2$. Since the new diameter is $D_2$, the new radius is half of it.
So, the new radius is 1.15 times the original radius.
Now we calculate the new area, $A_2$, using the new radius $r_2$:
$A_2 = \pi r_2^2 = \pi (1.15 r_1)^2 = \pi (1.15^2) r_1^2$
$A_2 = \pi (1.3225) r_1^2 = 1.3225 (\pi r_1^2)$
Since $A_1 = \pi r_1^2$, we can see that the new area is $A_2 = 1.3225 A_1$.
Alternatively, using the diameter form of the area formula:
$A_2 = \frac{\pi D_2^2}{4} = \frac{\pi (1.15 D_1)^2}{4} = \frac{\pi (1.15^2) D_1^2}{4} = 1.3225 \frac{\pi D_1^2}{4}$
Since $A_1 = \frac{\pi D_1^2}{4}$, we again find $A_2 = 1.3225 A_1$.
The percentage increase in area is calculated using the formula:
Percentage Increase = $\frac{\text{New Area} - \text{Original Area}}{\text{Original Area}} \times 100\%$
Percentage Increase = $\frac{A_2 - A_1}{A_1} \times 100\%$
Substitute $A_2 = 1.3225 A_1$ into the formula:
Percentage Increase = $\frac{1.3225 A_1 - A_1}{A_1} \times 100\%$
Percentage Increase = $\frac{(1.3225 - 1) A_1}{A_1} \times 100\%$
Percentage Increase = $\frac{0.3225 A_1}{A_1} \times 100\%$
Percentage Increase = $0.3225 \times 100\%$
Percentage Increase = $32.25\%$
Thus, if the diameter of a circle increases by 15%, its area increases by 32.25%.
| Parameter | Original | New (15% increase) |
|---|---|---|
| Diameter (D) | $D_1$ | $D_2 = 1.15 D_1$ |
| Radius (r) | $r_1 = D_1/2$ | $r_2 = D_2/2 = 1.15 D_1 / 2 = 1.15 r_1$ |
| Area (A) | $A_1 = \pi r_1^2$ | $A_2 = \pi r_2^2 = \pi (1.15 r_1)^2 = 1.3225 \pi r_1^2 = 1.3225 A_1$ |
The increase in area is $A_2 - A_1 = 1.3225 A_1 - A_1 = 0.3225 A_1$.
Percentage increase is $\frac{0.3225 A_1}{A_1} \times 100\% = 32.25\%$.
| Property | Formula (using radius r) | Formula (using diameter D) |
|---|---|---|
| Area (A) | $\pi r^2$ | $\frac{\pi D^2}{4}$ |
| Circumference (C) | $2\pi r$ | $\pi D$ |
| Relationship | $D = 2r$ or $r = D/2$ | |
When a quantity increases by a certain percentage, the new quantity is the original quantity multiplied by $(1 + \text{percentage increase as a decimal})$.
This method highlights that if a linear dimension (like diameter or radius) changes by a factor 'k', the area (which depends on the square of the linear dimension) changes by a factor 'k$^2$'. Here $k=1.15$, and $k^2 = 1.15^2 = 1.3225$. The percentage change is $(k^2 - 1) \times 100\% = (1.3225 - 1) \times 100\% = 0.3225 \times 100\% = 32.25\%$.
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