A square park having a side 20 m has two roads each 2 m wide running in the middle of it and parallel to its length and breath. What will be cost of gravelling the path at the rate of Rs. 100/m 2?
Rs. 7,600
This problem involves calculating the area of two paths (roads) running through the center of a square park and then finding the cost to gravel these paths. The park is square, meaning its length and breadth are equal. The roads run parallel to the sides of the park, intersecting in the middle.
Let's break down the given dimensions:
When two paths run through the middle of a rectangle or square, parallel to the sides, they will overlap in the center. The area of this overlap is the area of a square formed by the intersection of the two roads.
To find the total area of the paths, we can calculate the area of each path separately and then subtract the area of the central overlapping part, as it is counted twice.
The area of the road running parallel to the length is its length multiplied by its width. The length of this road within the park is equal to the side of the park.
Similarly, the area of the road running parallel to the breadth is its length (equal to the side of the park) multiplied by its width.
The two roads intersect in the middle. The shape of the intersection is a square with sides equal to the width of the roads.
The total area of the paths that needs gravelling is the sum of the areas of the two roads minus the area of the intersection (because it's included in both road area calculations).
Total Area of Paths = (Area of first road) + (Area of second road) - (Area of intersection)
Total Area of Paths = \(40 \text{ m}^2 + 40 \text{ m}^2 - 4 \text{ m}^2\)
Total Area of Paths = \(80 \text{ m}^2 - 4 \text{ m}^2\)
Total Area of Paths = \(76 \text{ m}^2\)
The cost of gravelling is given per square meter. We know the total area of the paths and the rate.
Cost of gravelling = Area of paths × Rate per m²
Cost = \(76 \text{ m}^2 \times \text{Rs. } 100/\text{m}^2\)
Cost = Rs. 7600
So, the total cost of gravelling the paths is Rs. 7,600.
| Item | Dimension/Value | Calculation | Area (m²) / Cost (Rs.) |
|---|---|---|---|
| Park Side | 20 m | - | - |
| Road Width | 2 m | - | - |
| Area of 1st Road | Length=20m, Width=2m | \(20 \times 2\) | 40 |
| Area of 2nd Road | Length=20m, Width=2m | \(20 \times 2\) | 40 |
| Area of Intersection | Side=2m | \(2 \times 2\) | 4 |
| Total Path Area | - | \(40 + 40 - 4\) | 76 |
| Gravelling Rate | Rs. 100/m² | - | - |
| Total Cost | Area=76 m², Rate=Rs. 100/m² | \(76 \times 100\) | 7600 |
| Concept | Formula / Method | Application in this Problem |
|---|---|---|
| Area of a rectangle | Length × Width | Used for calculating area of each road (treating it as a rectangle within the park). |
| Area of a square | Side × Side | Used for calculating the area of the intersection where the two roads overlap. |
| Area of intersecting paths (when parallel to sides) | Sum of individual path areas - Area of overlap | Used to find the net area covered by the roads, avoiding double-counting the intersection. Formula: \(A_{path1} + A_{path2} - A_{overlap}\). |
| Total Cost Calculation | Total Area × Rate per unit area | Used to find the total cost of gravelling by multiplying the net path area by the given rate per square meter. |
Calculating areas of paths within a rectangle or square is a common geometry problem. Here are some key points:
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