Sum of the solutions of the equations \(3x - 2(2x-5) = 2(x+3) - 8\) and \(3x = 5x - \frac{8}{5}\) is:
\(\frac{24}{5}\)
Solving the first equation, \(3x - 2(2x-5) = 2(x+3) - 8\) simplifies to \(3x - 4x + 10 = 2x + 6 - 8\), that is \(-x + 10 = 2x - 2\).
This gives \(-3x = -12\), so \(x = 4\).
Solving the second equation, \(3x = 5x - \frac{8}{5}\) gives \(-2x = -\frac{8}{5}\), so \(x = \frac{4}{5}\).
The sum of the two solutions is \(4 + \frac{4}{5} = \frac{24}{5}\).
Hence, the sum of the solutions is \(\frac{24}{5}\).
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