\(20xy - 4xz + 10y - 2z\) is equal to:
\(2(5y-z)(2x+1)\)
Grouping the terms, \(20xy - 4xz + 10y - 2z = (20xy + 10y) - (4xz + 2z)\).
Taking out common factors from each group, \(10y(2x+1) - 2z(2x+1)\).
Taking \((2x+1)\) common, this becomes \((2x+1)(10y-2z) = 2(2x+1)(5y-z)\).
Hence, \(20xy - 4xz + 10y - 2z\) is equal to \(2(5y-z)(2x+1)\).
Similar Questions
The sum of the coefficients of \(x^4\) and \(x^2\) in the product of \((x^2 - x + 4)\) and \((x^3 - 2x^2 + 3x + 1)\) is:
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