If \(\dfrac{3y}{4}-1=\dfrac{y}{3}\), then \(y\) is equal to :
\(2\dfrac{2}{5}\)
Given \(\dfrac{3y}{4}-1=\dfrac{y}{3}\).
Bringing the y-terms to one side: \(\dfrac{3y}{4}-\dfrac{y}{3}=1\).
Taking the LCM of 4 and 3, which is 12: \(\dfrac{9y-4y}{12}=1\).
\(\dfrac{5y}{12}=1\), so \(y=\dfrac{12}{5}\).
\(y=2\dfrac{2}{5}\).
Hence, y is equal to \(2\dfrac{2}{5}\).
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