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Question

The cost of a pen is five times the cost of a pencil. I bought 8 pens and 4 pencils for Rs. 132. Find the cost of 5 pens and 5 pencils.

The correct answer is

Rs. 90

Cost of Pens and Pencils Word Problem Solution

This problem requires us to find the combined cost of a specific number of pens and pencils, given their price relationship and a total purchase amount. We need to calculate the cost of 5 pens and 5 pencils.

Define Cost Variables

Let's represent the unknown costs using variables:

  • Let the cost of one pencil be '$x$' rupees.
  • The problem states that the cost of one pen is five times the cost of a pencil.
  • Therefore, the cost of one pen is '$5x$' rupees.

Formulate Cost Equation

We are given that the purchase of 8 pens and 4 pencils cost Rs. 132.

  • The total cost for 8 pens is $8 \times (\text{cost of one pen}) = 8 \times 5x = 40x$ rupees.
  • The total cost for 4 pencils is $4 \times (\text{cost of one pencil}) = 4 \times x = 4x$ rupees.
  • The sum of these costs equals the total amount spent:

$$40x + 4x = 132$$

Combining like terms:

$$44x = 132$$

Calculate Pencil Cost

To find the cost of a single pencil ('$x$'), we solve the equation:

$$x = \frac{132}{44}$$

Performing the division:

$$x = 3$$

So, the cost of one pencil is Rs. 3.

Calculate Pen Cost

Now we find the cost of one pen using the relationship '$5x$':

Cost of one pen = $5 \times 3 = 15$ rupees.

Calculate Final Cost

The question asks for the cost of 5 pens and 5 pencils.

  • Cost of 5 pens = $5 \times (\text{cost of one pen}) = 5 \times 15 = 75$ rupees.
  • Cost of 5 pencils = $5 \times (\text{cost of one pencil}) = 5 \times 3 = 15$ rupees.
  • The total cost for 5 pens and 5 pencils is the sum of their individual costs:

Total cost = $75 + 15 = 90$ rupees.

Thus, the cost of 5 pens and 5 pencils is Rs. 90.

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Important Questions from Linear Equation in 1 Variable

  1. What should be subtracted from p and added to q so that the resulting ratio becomes 1 : 5?

  2. Find the value of k, for which the system of equations kx + 3y = 26 and 21x + (k + 2)y = 71 + k has infinitely many solutions.

  3. If 2x 2 + 5x + 1 = 0, then one of the values of  \(\frac{1}{2}\left( {x\, - \,\frac{1}{{2x}}} \right)\)  is:

  4. 7225 Students are sitting in an auditorium in such a way that there are as many students in a row as there are rows in the auditorium. How many students are there in a row in the auditorium?

  5. Solve: 5(x + 43) = 2(3x + 4)

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