Ramagya spends 22% of his salary on house rent and 75% of the rest on household expenses. If he saves ₹3,705, find his total income (in rupees).
This problem involves calculating Ramagya's total income based on his spending on house rent and household expenses, and the amount he saves. We need to work backward from the savings to find the initial income.
Let's break down Ramagya's expenses:
We can represent Ramagya's total income as '$I$'.
If 22% is spent on rent, the remaining percentage is $100\% - 22\% = 78\%$.
Remaining salary = $78\%$ of Total Income = $0.78 \times I$.
He spends 75% of the *remaining* salary ($0.78 \times I$) on household expenses.
Household Expenses = $75\%$ of $(0.78 \times I) = 0.75 \times (0.78 \times I)$.
The amount saved is the remaining salary after rent, minus the household expenses.
Amount Saved = (Remaining Salary after Rent) - (Household Expenses)
Amount Saved = $(0.78 \times I) - (0.75 \times 0.78 \times I)$
We can factor out $(0.78 \times I)$:
Amount Saved = $(0.78 \times I) \times (1 - 0.75)$
Amount Saved = $(0.78 \times I) \times 0.25$
Amount Saved = $0.195 \times I$.
So, the savings represent 19.5% of the total income.
We know that the Amount Saved is ₹3,705, and this equals $0.195 \times I$.
$$ 3,705 = 0.195 \times I $$
To find the total income ($I$), we rearrange the equation:
$$ I = \frac{3,705}{0.195} $$
$$ I = \frac{3,705,000}{195} $$
$$ I = 19,000 $$
| Expense Category | Percentage of Total Income | Calculation |
|---|---|---|
| House Rent | 22% | $0.22 \times I$ |
| Remaining after Rent | $100\% - 22\% = 78\%$ | $0.78 \times I$ |
| Household Expenses | $75\%$ of $78\% = 58.5\%$ | $0.75 \times (0.78 \times I) = 0.585 \times I$ |
| Savings | $78\% - 58.5\% = 19.5\%$ | $(0.78 \times I) - (0.585 \times I) = 0.195 \times I$ |
Ramagya's total income is ₹19,000.
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