In an examination, Ram obtained 20 % more than Ashok but 10% less than Rajesh. If the marks obtained by Ashok is 1080. Then the Percentage marks obtained by Rajesh if the full marks is 2000 ;
72%
The question asks us to find the percentage marks obtained by Rajesh in an examination, given the marks of Ashok and the relative performance of Ram compared to both Ashok and Rajesh. The total marks for the examination are also provided.
Ram obtained 20% more than Ashok. First, let's find 20% of Ashok's marks.
\(\text{20% of Ashok's marks} = \frac{20}{100} \times 1080\)
\(= \frac{1}{5} \times 1080\)
\(= 216\)
Ram's marks are Ashok's marks plus 20% of Ashok's marks.
\(\text{Ram's marks} = 1080 + 216\)
\(= 1296\)
So, Ram obtained 1296 marks.
Ram obtained 10% less than Rajesh. This means Ram's marks are 90% of Rajesh's marks (100% - 10% = 90%).
Let Rajesh's marks be \(R\).
\(\text{Ram's marks} = 90\% \text{ of } R\)
\(1296 = \frac{90}{100} \times R\)
\(1296 = \frac{9}{10} \times R\)
To find \(R\), we can rearrange the equation:
\(R = 1296 \times \frac{10}{9}\)
\(R = \frac{12960}{9}\)
\(R = 1440\)
So, Rajesh obtained 1440 marks.
The full marks for the examination are 2000. To find the percentage marks obtained by Rajesh, we use the formula:
\(\text{Percentage} = \frac{\text{Marks Obtained}}{\text{Full Marks}} \times 100\)
\(\text{Rajesh's Percentage Marks} = \frac{1440}{2000} \times 100\)
\(= \frac{1440}{20}\)
\(= 72\)
So, Rajesh obtained 72% marks.
| Student | Marks Obtained |
|---|---|
| Ashok | 1080 |
| Ram | 1296 |
| Rajesh | 1440 |
Rajesh obtained 1440 marks out of a total of 2000 marks, which is 72%.
Based on the calculations, the percentage marks obtained by Rajesh is 72%.
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