A person, while trading the shares of a particular company, observes that its price has gone down by 10% from the previous day. In anticipation of increment on the next day, he holds it for the next day. But the share price further falls down by another 8% of the previous day. Then he sells his shares and gets ₹12,420. How much could he have saved had he sold it the previous day?
This problem involves calculating potential savings in share trading after consecutive price drops. We need to determine the original price of the share and the price at which it was sold, then compare this to the price it would have been sold for on the previous day.
Let's break down the information given:
To solve this, we'll work backward from the final selling price. Let's assume the price of the share at the beginning of the first day (original price) was '$P$'.
Price after the first day's drop: The price decreased by 10%. The remaining value is 100% - 10% = 90% of the original price.
Price = $P \times (1 - 0.10) = 0.90P$
This '$0.90P$' represents the share price at the end of the previous day (before the second drop occurred).
Price after the second day's drop: The price fell by another 8% of the price at the end of the previous day ($0.90P$).
The remaining value is 100% - 8% = 92% of the price at the end of the previous day.
Final Selling Price = $(0.90P) \times (1 - 0.08) = 0.90P \times 0.92 = 0.828P$
We know the final selling price is ₹12,420. Using our calculation from the previous step:
$$0.828P = 12,420$$
Now, we can find the original price '$P$':
$$P = \frac{12,420}{0.828}$$
$$P = 15,000$$
So, the original price of the share was ₹15,000.
Next, let's find the price at the end of the previous day (after the first 10% drop):
Price on previous day = $0.90P = 0.90 \times 15,000 = 13,500$
The share price at the end of the previous day was ₹13,500.
The person sold the shares for ₹12,420. Had they sold it on the previous day, they would have received ₹13,500.
The amount the person could have saved is the difference between the price on the previous day and the final selling price:
Amount Saved = Price on previous day - Final Selling Price
Amount Saved = $₹13,500 - ₹12,420$
Amount Saved = $₹1,080$
Therefore, the person could have saved ₹1,080 had they sold the shares on the previous day.
The price of an AC increases and decreases in every alternate year by $1\frac{3}{5}\%$. It started with an increase in 2004. The price of the AC in 2007, as compared to that in 2004 (correct to two places of decimals):
The sum of the two numbers is 450. If the greater number is decreased by 4% and the smaller number is increased by 20%, then the numbers obtained are equal. The smaller number is:
In an examination, 25% of the candidates failed in Mathematics and 12% failed in English. If 10% of the candidates failed in both the subjects and 292 candidates passed in both the subjects, which one of the following is the number of total candidates appeared in the examination?
What is the value of 9% of 5500 + 2.4% of 1100 - 40% of 1600?
Population of a village is 7960 in which 4660 are female. If in that village 60% are literate in which 70% female are literate, then what is the number of literate male ?
In an examination, Ram obtained 20 % more than Ashok but 10% less than Rajesh. If the marks obtained by Ashok is 1080. Then the Percentage marks obtained by Rajesh if the full marks is 2000 ;
A student appeared in 6 papers. The maximum marks are the same for each paper. His marks in these papers are in the proportion of 5 : 6 : 7 : 8 : 9 : 10. Overall he scored 60%. In how many number of papers did he score less than 60% of the maximum marks?