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Question

The present population of a city is 60,000. If the rate of increase is 10% per year, find the population of the city after 2 years.

This question was previously asked in
SSC Selection Post 2022 Matriculation Level Question Paper (02-Aug-2022) (Shift-4)
The correct answer is
72600

Understanding Population Growth Calculation

The question asks us to calculate the future population of a city based on its current population and a consistent annual growth rate over a specific period. This is a typical compound growth problem.

Given Information:

  • Present Population (P): 60,000
  • Annual Rate of Increase (R): 10%
  • Time Period (T): 2 years

Calculating Future City Population

To find the population after 2 years, we can use the formula for compound growth, which is similar to the formula used for compound interest:

Future Population = Present Population $\times$ (1 + Rate of Increase / 100)$^{\text{Number of Years}}$

In mathematical terms:

Future Population = $P \times \left(1 + \frac{R}{100}\right)^T$

Step-by-Step Calculation:

  1. Substitute the values into the formula:

    Future Population = $60,000 \times \left(1 + \frac{10}{100}\right)^2$

  2. Simplify the term inside the parenthesis:

    $\frac{10}{100} = 0.10$

    So, $\left(1 + \frac{10}{100}\right) = (1 + 0.10) = 1.10$

  3. Calculate the exponential term:

    $(1.10)^2 = 1.10 \times 1.10 = 1.21$

  4. Multiply the present population by the result:

    Future Population = $60,000 \times 1.21$

    Future Population = $72,600$

Conclusion

After 2 years, with a consistent 10% annual increase rate, the population of the city will be 72,600.

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