Raj is 60% more efficient than Sundar. This means Raj's work rate is higher.
If Sundar's efficiency is represented as 100%, Raj's efficiency is:
$100\% + 60\% = 160\%$ of Sundar's efficiency.
The ratio of their efficiencies is:
$\text{Efficiency}_{\text{Raj}} : \text{Efficiency}_{\text{Sundar}} = 160 : 100 = 8 : 5$.
Work and time are inversely related. Higher efficiency means less time is needed.
The ratio of time taken is the inverse of the efficiency ratio:
$\text{Time}_{\text{Raj}} : \text{Time}_{\text{Sundar}} = 5 : 8$.
Given Sundar takes $T_{Sundar}$ = 16 days.
Let Raj take $T_{Raj}$ days. The relationship is:
$\frac{T_{Raj}}{T_{Sundar}} = \frac{5}{8}$
Substituting Sundar's time:
$\frac{T_{Raj}}{16} = \frac{5}{8}$
Solving for $T_{Raj}$:
$T_{Raj}$ $= 16 \times \frac{5}{8}$
$T_{Raj}$ $= 10$ days.
Therefore, Raj will alone take 10 days to complete the same task.
Manoj is twice as efficient a fisherman as Anuraj, and together they complete a piece of work in 22 days. In how many days can Anuraj alone complete the same work?
A and B together can complete a certain work in 20 days whereas B and C together can complete it in 24 days. If A is twice as good a workman as C, then in what time will B alone do 40% of the same work?
14 men can complete a work in 15 days. If 21 men are employed, then in how many days will they complete the same work?
A can do a certain work in 15 days, while B can do the same work in 21 days. If they work together, then in how many days will the same work be completed?
To do a certain work, A and B work on alternate days with B beginning the work on the first day. A alone can complete the same work in 24 days. If the work gets completed in \(11 \frac{1}{3}\) days, then B alone can complete \(\rm \frac{7}{9}^{th}\) part of the original work in:
Two men and 7 women can complete a work in 28 days whereas 6 men and 16 women can do the same work in 11 days. In how many days can 7 men complete the same work?