Raj is 60% more efficient than Sundar. This means Raj's work rate is higher.
If Sundar's efficiency is represented as 100%, Raj's efficiency is:
$100\% + 60\% = 160\%$ of Sundar's efficiency.
The ratio of their efficiencies is:
$\text{Efficiency}_{\text{Raj}} : \text{Efficiency}_{\text{Sundar}} = 160 : 100 = 8 : 5$.
Work and time are inversely related. Higher efficiency means less time is needed.
The ratio of time taken is the inverse of the efficiency ratio:
$\text{Time}_{\text{Raj}} : \text{Time}_{\text{Sundar}} = 5 : 8$.
Given Sundar takes $T_{Sundar}$ = 16 days.
Let Raj take $T_{Raj}$ days. The relationship is:
$\frac{T_{Raj}}{T_{Sundar}} = \frac{5}{8}$
Substituting Sundar's time:
$\frac{T_{Raj}}{16} = \frac{5}{8}$
Solving for $T_{Raj}$:
$T_{Raj}$ $= 16 \times \frac{5}{8}$
$T_{Raj}$ $= 10$ days.
Therefore, Raj will alone take 10 days to complete the same task.
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