This problem involves comparing the work efficiency and time taken by two individuals, Raju and Ravi.
Let the time taken by Ravi to complete the piece of work be $T_R$ days.
Let the time taken by Raju to complete the same work be $T_J$ days.
We are given that Raju is thrice as good a workman as Ravi. This means Raju's work rate is 3 times Ravi's work rate.
When one person's work rate is higher, they take less time to complete the same amount of work. Specifically, if Raju's rate is 3 times Ravi's, Raju's time will be 1/3 of Ravi's time.
Therefore, the relationship between their times is: $T_J = \frac{T_R}{3}$
We are also given that Raju takes 20 days less than Ravi to complete the work. This can be written as: $T_J = T_R - 20$
Equate the two expressions for Raju's time ($T_J$): $ \frac{T_R}{3} = T_R - 20 $
To eliminate the fraction, multiply both sides of the equation by 3: $ 3 \times \frac{T_R}{3} = 3 \times (T_R - 20) $ $ T_R = 3T_R - 60 $
Rearrange the equation to group the terms with $T_R$ on one side: $ 60 = 3T_R - T_R $ $ 60 = 2T_R $
Solve for $T_R$ by dividing by 2: $ T_R = \frac{60}{2} $ $ T_R = 30 $
So, the time taken by Ravi to complete the work is 30 days.
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