This problem requires calculating the total time to complete a task considering different work efficiencies and a condition where one person leaves before the task finishes.
The approach involves determining individual work rates, calculating total work, and then analyzing the work done during different phases.
Let's define the work rate of person A. We'll assume A's work rate is 1 unit per day.
A completes the work in 45 days. The total amount of work ($W$) can be calculated as:
$W = R_A \times 45 \text{ days} = 1 \text{ unit/day} \times 45 \text{ days} = 45 \text{ units}$
When A, B, and C work together, their combined work rate ($R_{ABC}$) is:
$R_{ABC} = R_A + R_B + R_C = 1 + 1.5 + 3 = 5.5 \text{ units/day}$
When only A and B work together, their combined work rate ($R_{AB}$) is:
$R_{AB} = R_A + R_B = 1 + 1.5 = 2.5 \text{ units/day}$
C left 7 days before the work was completed. This implies that A and B worked together for the final 7 days.
Calculate the work done by A and B during these last 7 days ($W_{last7}$):
$W_{last7} = R_{AB} \times 7 \text{ days} = 2.5 \text{ units/day} \times 7 \text{ days} = 17.5 \text{ units}$
The work done by all three (A, B, and C) before C left ($W_{ABC}$) is the total work minus the work done in the last 7 days:
$W_{ABC} = W - W_{last7} = 45 \text{ units} - 17.5 \text{ units} = 27.5 \text{ units}$
The number of days A, B, and C worked together ($Days_{ABC}$) is found by dividing the work they did together by their combined rate:
$Days_{ABC} = \frac{W_{ABC}}{R_{ABC}} = \frac{27.5 \text{ units}}{5.5 \text{ units/day}} = 5 \text{ days}$
The total time taken to complete the entire work is the sum of the days A, B, and C worked together and the final 7 days when only A and B worked.
Total Days = Days A, B, C worked + Days A, B worked alone
Total Days = 5 days + 7 days = 12 days
Therefore, the entire work was completed in 12 days.
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24 men and 12 women can do a piece of work in 30 days. In how many days can 12 men and 24 women do the same piece of work?
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A is thrice as good a workman as B. C alone takes 48 days to paint a house. All three A, B and C working together take 16 days to paint the house. It will take how many days for A alone to paint the house?