This problem requires calculating the total time to complete a task considering different work efficiencies and a condition where one person leaves before the task finishes.
The approach involves determining individual work rates, calculating total work, and then analyzing the work done during different phases.
Let's define the work rate of person A. We'll assume A's work rate is 1 unit per day.
A completes the work in 45 days. The total amount of work ($W$) can be calculated as:
$W = R_A \times 45 \text{ days} = 1 \text{ unit/day} \times 45 \text{ days} = 45 \text{ units}$
When A, B, and C work together, their combined work rate ($R_{ABC}$) is:
$R_{ABC} = R_A + R_B + R_C = 1 + 1.5 + 3 = 5.5 \text{ units/day}$
When only A and B work together, their combined work rate ($R_{AB}$) is:
$R_{AB} = R_A + R_B = 1 + 1.5 = 2.5 \text{ units/day}$
C left 7 days before the work was completed. This implies that A and B worked together for the final 7 days.
Calculate the work done by A and B during these last 7 days ($W_{last7}$):
$W_{last7} = R_{AB} \times 7 \text{ days} = 2.5 \text{ units/day} \times 7 \text{ days} = 17.5 \text{ units}$
The work done by all three (A, B, and C) before C left ($W_{ABC}$) is the total work minus the work done in the last 7 days:
$W_{ABC} = W - W_{last7} = 45 \text{ units} - 17.5 \text{ units} = 27.5 \text{ units}$
The number of days A, B, and C worked together ($Days_{ABC}$) is found by dividing the work they did together by their combined rate:
$Days_{ABC} = \frac{W_{ABC}}{R_{ABC}} = \frac{27.5 \text{ units}}{5.5 \text{ units/day}} = 5 \text{ days}$
The total time taken to complete the entire work is the sum of the days A, B, and C worked together and the final 7 days when only A and B worked.
Total Days = Days A, B, C worked + Days A, B worked alone
Total Days = 5 days + 7 days = 12 days
Therefore, the entire work was completed in 12 days.
Manoj is twice as efficient a fisherman as Anuraj, and together they complete a piece of work in 22 days. In how many days can Anuraj alone complete the same work?
A and B together can complete a certain work in 20 days whereas B and C together can complete it in 24 days. If A is twice as good a workman as C, then in what time will B alone do 40% of the same work?
14 men can complete a work in 15 days. If 21 men are employed, then in how many days will they complete the same work?
A can do a certain work in 15 days, while B can do the same work in 21 days. If they work together, then in how many days will the same work be completed?
To do a certain work, A and B work on alternate days with B beginning the work on the first day. A alone can complete the same work in 24 days. If the work gets completed in \(11 \frac{1}{3}\) days, then B alone can complete \(\rm \frac{7}{9}^{th}\) part of the original work in:
Two men and 7 women can complete a work in 28 days whereas 6 men and 16 women can do the same work in 11 days. In how many days can 7 men complete the same work?