The question asks to determine which individual among A, B, C, and D will complete a given piece of work first, assuming they start simultaneously. To find this, we need to calculate the total time each person requires to finish the entire work.
We are given the fraction of work each person completes in a specific number of days. We can use this information to find the time needed for each to complete 1 whole unit of work.
Completes $\frac{1}{5}$ of the work in 12 days.
Time for A to complete the whole work = $12 \times 5 = 60$ days.
Completes $20\%$ of the work in 10 days. Since $20\% = \frac{20}{100} = \frac{1}{5}$, B completes $\frac{1}{5}$ of the work in 10 days.
Time for B to complete the whole work = $10 \times 5 = 50$ days.
Completes $\frac{1}{6}$ of the work in 8 days.
Time for C to complete the whole work = $8 \times 6 = 48$ days.
Completes $\frac{1}{5}$ of the work in 12 days.
Time for D to complete the whole work = $12 \times 5 = 60$ days.
Now, let's compare the total time each person needs to complete the work:
The individual who requires the minimum time to complete the work will finish first. Comparing the times, C requires the least time (48 days).
Therefore, C will complete the work first if all four started to work at the same time.
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