The problem involves calculating the time required for a group of men to complete a work, given information about women completing the same work and the relative work capacities of men and women.
First, determine the total amount of work. The total work is the product of the number of workers, their individual rate, and the time taken.
Given: 5 women can do the work in 36 days.
Let $R_w$ represent the work rate of one woman.
Total Work = (Number of Women) $\times$ (Days) $\times$ (Rate of one Woman)
Total Work $= 5 \times 36 \times R_w = 180 R_w$ units of work.
The ratio between the capacity (work rate) of a man ($R_m$) and a woman ($R_w$) is given as 3:1.
This means $\frac{R_m}{R_w} = \frac{3}{1}$, which implies $R_m = 3 R_w$. A man works three times as fast as a woman.
Now, calculate the time it takes for 5 men to complete the same total work.
Let $D$ be the number of days it takes for 5 men to complete the work.
Total Work = (Number of Men) $\times$ (Days) $\times$ (Rate of one Man)
Using the total work calculated earlier:
$180 R_w = 5 \times D \times R_m$
Substitute the relationship $R_m = 3 R_w$ into the equation:
$180 R_w = 5 \times D \times (3 R_w)$
$180 R_w = 15 D R_w$
To find $D$, divide both sides by $15 R_w$ (assuming $R_w \neq 0$):
$D = \frac{180}{15}$
$D = 12$
Therefore, it will take 5 men 12 days to complete the same work.
Manoj is twice as efficient a fisherman as Anuraj, and together they complete a piece of work in 22 days. In how many days can Anuraj alone complete the same work?
A and B together can complete a certain work in 20 days whereas B and C together can complete it in 24 days. If A is twice as good a workman as C, then in what time will B alone do 40% of the same work?
14 men can complete a work in 15 days. If 21 men are employed, then in how many days will they complete the same work?
A can do a certain work in 15 days, while B can do the same work in 21 days. If they work together, then in how many days will the same work be completed?
To do a certain work, A and B work on alternate days with B beginning the work on the first day. A alone can complete the same work in 24 days. If the work gets completed in \(11 \frac{1}{3}\) days, then B alone can complete \(\rm \frac{7}{9}^{th}\) part of the original work in:
Two men and 7 women can complete a work in 28 days whereas 6 men and 16 women can do the same work in 11 days. In how many days can 7 men complete the same work?