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Question

Match List - I with List - II.

List - I (Feedback connection type) List - II (Input/output impedance) 
(A) Voltage series feedback(I) \(Z_{of}=\dfrac{Z_{o}}{1+\beta A}\)
(B) Voltage shunt feedback(II) \(Z_{of}=Z_{o}\left(1+\beta A\right)\)
(C) Current series feedback(III) \(Z_{if}=\dfrac{Z_{i}}{1+\beta A}\)
(D) Current shunt feedback(IV) \(Z_{if}=Z_{i}\left(1+\beta A\right)\)

Choose the correct answer from the options given below :

This question was previously asked in
UGC NET 2023 Electronic Science Question Paper (13-Dec-2023) (Shift 1)
The correct answer is

(A)-(IV), (B)-(I), (C)-(II), (D)-(III)

 Two rules settle every entry, and they are entirely independent of one another :

Half of the nameRefers toEffect
Series mixingInputRaises Zi by (1 + βA)
Shunt mixingInputLowers Zi by (1 + βA)
Voltage samplingOutputLowers Zo by (1 + βA)
Current samplingOutputRaises Zo by (1 + βA)

Applying them.

(A) Voltage series — series mixing raises the input impedance, so \(Z_{if}=Z_{i}\left(1+\beta A\right)\), which is (IV).

(B) Voltage shunt — voltage sampling lowers the output impedance, so \(Z_{of}=Z_{o}/\left(1+\beta A\right)\), which is (I).

(C) Current series — current sampling raises the output impedance, so \(Z_{of}=Z_{o}\left(1+\beta A\right)\), which is (II).

(D) Current shunt — shunt mixing lowers the input impedance, so \(Z_{if}=Z_{i}/\left(1+\beta A\right)\), which is (III).

— option 4.

Why series raises and shunt lowers the input impedance. With series mixing the feedback voltage is subtracted in series with the source, so the source must supply a larger voltage to force the same input current — and a larger voltage for the same current is a higher impedance. With shunt mixing the feedback current is subtracted at the input node, so the source must supply more current at the same voltage — a lower impedance.

Why voltage sampling lowers and current sampling raises the output impedance. Voltage sampling makes the amplifier defend its output voltage against changes of load, which is what a low output impedance means. Current sampling makes it defend its output current, which is what a high output impedance means. In each case the feedback holds constant whatever it senses.

This is why the topology is chosen, not accepted. A voltage amplifier wants high input and low output impedance, so it uses voltage-series feedback; a current amplifier wants the opposite and uses current-shunt. The four topologies exist precisely because the two sampling and two mixing choices can be combined independently.

Hence, the correct code is (A)-(IV), (B)-(I), (C)-(II), (D)-(III).

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Similar Questions

  1. Match the following lists :

    List – I List – II 
    a. Voltage series feedbacki. Trans resistance amplifier
    b. Current series feedbackii. Current shunt feedback
    c. Current amplifieriii. Trans-conductance
    d. Voltage shunt feedbackiv. Voltage amplifier

    Codes :

  2. Match the following :

    List – I List – II 
    a. voltage shunt negative feedbacki. increase of CMRR
    b. constant current source differential amplifierii. O/P voltage attenuated by a factor 1/29
    c. Phase shift oscillatoriii. FSK decoder
    d. PLLiv. decrease of O/P impedance

    Codes :

  3. Negative feedback in amplifier results in

    1. reduced voltage gain
    2. reduced bandwidth
    3. increased S/N ratio
    4. reduced distortion

  4. An amplifier has open-loop voltage gain of 40. 10 % of negative feedback is effected. What will be the gain with feedback ?

  5. Given below are two statements :

    Statement I : For negative feedback systems, the open loop gain decreases by a certain factor.

    Statement II : Negative feedback systems are better in terms of system stability

    In the light of the above statements, choose the correct answer from the options given below :

  6. Negative Feedback in amplifiers :

    (a) improves signal to noise ratio at the output

    (b) increases distortion

    (c) reduces input offset voltage

    (d) increases bandwidth

    Options :

  7. Read the following statements :

    (a) Whatever the mode of feedback be, the gain after negative feedback is \(\dfrac{A}{1+A\beta}\)
    (b) A negative feedback reduces the bandwidth of the amplifier.
    (c) A negative feedback increases the output impedance
    (d) A negative feedback enhances the stability of operation

    Which of the above statements are correct ?


Important Questions from Feedback Amplifier

  1. The effect of negative feedback is to increase the __________ of a series voltage negative feedback amplifier by a factor of (1 + A vβ).

  2. Which of the following improvement is obtained in negative feedback amplifier?

  3. Feedback in an amplifier always helps to ________

  4. What is the effect of current shunt feedback in an amplifier?

  5. The output impedance of a voltage series feedback is 10 Ω, If the gain of the basic amplifier is 100 and feedback fraction is 0.01, what is the output impedance without feedback?
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