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An amplifier has open-loop voltage gain of 40. 10 % of negative feedback is effected. What will be the gain with feedback ?

This question was previously asked in
UGC NET 2014 Paper 1 Question Paper (28-Dec-2014)
The correct answer is

8

 Substitute directly into the negative-feedback formula.

\(A_{f}=\dfrac{A}{1+A\beta}\)

with \(A=40\) and \(\beta=0.1\):

\(A\beta=40\times0.1=4\)

\(A_{f}=\dfrac{40}{1+4}=\dfrac{40}{5}=8\)

— option 4.

Reading the numbers. "10 % of negative feedback" means one tenth of the output is returned to the input in opposition, so \(\beta=0.1\). The quantity \(A\beta=4\) is the loop gain, and \(1+A\beta=5\) is the amount of feedback or desensitivity factor — the factor by which everything about the amplifier is improved, and by which the gain is reduced.

PropertyEffect of the feedbackHere
GainDivided by 1 + Aβ40 → 8
Gain stabilityImproved by 1 + Aβ5× steadier
BandwidthMultiplied by 1 + Aβ5× wider
DistortionDivided by 1 + Aβ5× lower
Input impedance (series)Multiplied by 1 + Aβ5× higher
Output impedance (voltage)Divided by 1 + Aβ5× lower

What the trade buys. Gain is the one thing given up, and it is the cheapest thing to give up because more stages can always supply it. Everything else improves by the same factor of 5. The stability improvement is the most valuable:

\(\dfrac{dA_{f}}{A_{f}}=\dfrac{1}{1+A\beta}\dfrac{dA}{A}\)

so a 20 % change in the open-loop gain — from temperature, ageing, or device spread — becomes a 4 % change in the closed-loop gain here.

The limiting case is worth noting: when \(A\beta\gg1\), the formula collapses to \(A_{f}\approx1/\beta\) — the gain depends only on the feedback network, and not on the amplifier at all. That is why an op-amp circuit's gain is set purely by two resistors. With \(A\beta=4\) the approximation would give 10 against the true 8, so this amplifier is not yet deep enough into feedback for it to hold.

Hence, the gain with feedback is 8.

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Similar Questions

  1. Match the following lists :

    List – I List – II 
    a. Voltage series feedbacki. Trans resistance amplifier
    b. Current series feedbackii. Current shunt feedback
    c. Current amplifieriii. Trans-conductance
    d. Voltage shunt feedbackiv. Voltage amplifier

    Codes :

  2. Match the following :

    List – I List – II 
    a. voltage shunt negative feedbacki. increase of CMRR
    b. constant current source differential amplifierii. O/P voltage attenuated by a factor 1/29
    c. Phase shift oscillatoriii. FSK decoder
    d. PLLiv. decrease of O/P impedance

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  3. Negative feedback in amplifier results in

    1. reduced voltage gain
    2. reduced bandwidth
    3. increased S/N ratio
    4. reduced distortion

  4. Match List - I with List - II.

    List - I (Feedback connection type) List - II (Input/output impedance) 
    (A) Voltage series feedback(I) \(Z_{of}=\dfrac{Z_{o}}{1+\beta A}\)
    (B) Voltage shunt feedback(II) \(Z_{of}=Z_{o}\left(1+\beta A\right)\)
    (C) Current series feedback(III) \(Z_{if}=\dfrac{Z_{i}}{1+\beta A}\)
    (D) Current shunt feedback(IV) \(Z_{if}=Z_{i}\left(1+\beta A\right)\)

    Choose the correct answer from the options given below :

  5. Given below are two statements :

    Statement I : For negative feedback systems, the open loop gain decreases by a certain factor.

    Statement II : Negative feedback systems are better in terms of system stability

    In the light of the above statements, choose the correct answer from the options given below :

  6. Negative Feedback in amplifiers :

    (a) improves signal to noise ratio at the output

    (b) increases distortion

    (c) reduces input offset voltage

    (d) increases bandwidth

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  7. Read the following statements :

    (a) Whatever the mode of feedback be, the gain after negative feedback is \(\dfrac{A}{1+A\beta}\)
    (b) A negative feedback reduces the bandwidth of the amplifier.
    (c) A negative feedback increases the output impedance
    (d) A negative feedback enhances the stability of operation

    Which of the above statements are correct ?


Important Questions from Feedback Amplifier

  1. The effect of negative feedback is to increase the __________ of a series voltage negative feedback amplifier by a factor of (1 + A vβ).

  2. Which of the following improvement is obtained in negative feedback amplifier?

  3. Feedback in an amplifier always helps to ________

  4. What is the effect of current shunt feedback in an amplifier?

  5. The output impedance of a voltage series feedback is 10 Ω, If the gain of the basic amplifier is 100 and feedback fraction is 0.01, what is the output impedance without feedback?
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