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Question

What is the main disadvantage of a half-wave rectifier?

This question was previously asked in
RRB JE 2025 CBT 2 Mechanical and Allied Engg Question Paper English (2-Jul-2026) (Shift-1)
The correct answer is

Utilizes only one half-cycle

A half-wave rectifier is a type of rectifier that only allows one half-cycle of an AC voltage waveform to pass through as it converts AC to DC. Let's analyze the main disadvantage of a half-wave rectifier and identify why the correct answer is "Utilizes only one half-cycle".

Explanation:

  • The half-wave rectifier only utilizes one half-cycle of the input AC signal—either the positive half-cycle or the negative half-cycle. Consequently, it only rectifies half of the input signal.
  • The efficiency of a half-wave rectifier is lower because it effectively discards half of the input signal. This results in higher power loss and inefficient use of the AC power supply.
  • Due to only one half-cycle being used, the output is less smooth and has a higher ripple factor, requiring additional filtering to produce a steady DC output.

Consideration of Other Options:

  • Ripple frequency equal to supply frequency: This is indeed a characteristic of half-wave rectifiers, but it is not inherently a disadvantage. Instead, it's a technical specification.
  • Requires center-tap transformer: This is not applicable to a basic half-wave rectifier. A center-tap transformer is typically associated with a full-wave rectifier.
  • High cost: Half-wave rectifiers are generally less expensive to construct due to their simplicity, making this an incorrect disadvantage.

Conclusion:

The main disadvantage of a half-wave rectifier is that it only utilizes one half-cycle of the input AC signal, leading to lower efficiency and higher ripple in the output. This results in the correct option being: "Utilizes only one half-cycle".

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Similar Questions

  1. Before breakdown, increasing reverse voltage causes reverse saturation current to __________.

  2. The existence of cut-in voltage in a diode is mainly due to the presence of __________.

  3. Consider an abrupt p-n junction under thermal equilibrium. If the acceptor doping concentration (NA) in the p-region is made significantly larger than the donor doping concentration (ND) in the n-region (i.e., $N_A ≫ N_D$), how is the depletion region physically distributed?

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Important Questions from PN Junction

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