The problem describes a scenario with two related simple interest transactions. We need to find the initial principal amount based on the profit earned by Arif.
Let the principal amount lent by Kumar to Arif be '$P$'.
The formula for Simple Interest (SI) is given by:
$SI = \frac{P \times R \times T}{100}$Calculate the interest Arif pays to Kumar:
$SI_{paid} = \frac{P \times 10 \times 3}{100} = \frac{30P}{100}$Calculate the interest Arif receives from Naresh:
$SI_{received} = \frac{P \times 20 \times 3}{100} = \frac{60P}{100}$Arif's profit is the difference between the interest he received and the interest he paid:
$Profit = SI_{received} - SI_{paid}$We are given that Arif's profit is ₹1,560:
$\frac{60P}{100} - \frac{30P}{100} = 1560$Combine the terms:
$\frac{(60 - 30)P}{100} = 1560$ $\frac{30P}{100} = 1560$To find the principal amount $P$, rearrange the equation:
$0.30 \times P = 1560$ $P = \frac{1560}{0.30}$ $P = \frac{15600}{3}$ $P = 5200$The amount that Kumar lent to Arif was ₹5,200.
Anil lent a sum of Rs. 5,000 on simple interest for 10 years in such a way that the rate of interest is 6% per annum for the first 2 years, 8% per anmum for the next 2 years and 10% per annum beyond 4 years. How much interest (in Rs.) will he earn at the end of 10 years?
What will be the simple interest on a sum of Rs. 12000 at the rate of 15 percent per annum for three years ?
If in 13 years fixed sum doubles at simple interest, what will be the interest rate per year? (correct to two decimal places)
On simple interest a sum of Rs. 640 becomes Rs. 832 in 2 years. What will Rs. 860 become in 4 years at the same rate of simple interest?
A certain sum amounts to Rs. 81840 in 3 years and to Rs. 92400 in 5 years at x% p.a. under simple interest. If the rate of interest is becomes (x + 2)%, then in how many years will the same sum double itself?