The problem involves calculating the final amount after a simple interest rate increase.
Simple Interest is the difference between the final amount and the principal.
$SI = A - P$
$SI = ₹920 - ₹800 = ₹120$
Using the simple interest formula: $SI = (P × R × T) / 100$
$120 = \frac{800 \times R \times 3}{100}$
$120 = 8 \times R \times 3$
$120 = 24 \times R$
$R = \frac{120}{24} = 5\%$
The initial rate of interest is 5% per annum.
The interest rate is increased by 4%.
$New Rate (R_new) = Initial Rate (R) + 4%$
$R_new = 5\% + 4\% = 9\%$
Using the new rate (9%) with the same principal and time.
$SI_{new} = \frac{P \times R_{new} \times T}{100}$
$SI_{new} = \frac{800 \times 9 \times 3}{100}$
$SI_{new} = 8 \times 9 \times 3$
$SI_{new} = ₹216$
The new amount is the sum of the principal and the new simple interest.
$New Amount (A_new) = P + SI_new$
$A_{new} = ₹800 + ₹216$
$A_{new} = ₹1016$
Anil lent a sum of Rs. 5,000 on simple interest for 10 years in such a way that the rate of interest is 6% per annum for the first 2 years, 8% per anmum for the next 2 years and 10% per annum beyond 4 years. How much interest (in Rs.) will he earn at the end of 10 years?
What will be the simple interest on a sum of Rs. 12000 at the rate of 15 percent per annum for three years ?
If in 13 years fixed sum doubles at simple interest, what will be the interest rate per year? (correct to two decimal places)
On simple interest a sum of Rs. 640 becomes Rs. 832 in 2 years. What will Rs. 860 become in 4 years at the same rate of simple interest?
A certain sum amounts to Rs. 81840 in 3 years and to Rs. 92400 in 5 years at x% p.a. under simple interest. If the rate of interest is becomes (x + 2)%, then in how many years will the same sum double itself?