The problem asks for the annual simple interest rate (R) when an initial amount (Principal, P) grows to a new amount (A) in a given time (T).
The Simple Interest earned is the difference between the final Amount and the Principal:
$ SI = A - P $
Substituting the value of A:
$ SI = \frac{8}{5}P - P $
To subtract, find a common denominator:
$ SI = \frac{8}{5}P - \frac{5}{5}P $
$ SI = \frac{8 - 5}{5}P $
$ SI = \frac{3}{5}P $
The formula for Simple Interest is:
$ SI = \frac{P \times R \times T}{100} $
We know SI = $\frac{3}{5}P$ and T = 5 years. Substitute these values into the formula:
$ \frac{3}{5}P = \frac{P \times R \times 5}{100} $
We can cancel out P from both sides of the equation (assuming P is not zero):
$ \frac{3}{5} = \frac{R \times 5}{100} $
Now, solve for R. First, simplify the right side:
$ \frac{3}{5} = \frac{5R}{100} $
Multiply both sides by 100 to isolate 5R:
$ \frac{3}{5} \times 100 = 5R $
$ 3 \times 20 = 5R $
$ 60 = 5R $
Divide by 5 to find R:
$ R = \frac{60}{5} $
$ R = 12 $
Therefore, the simple interest rate is 12% per annum.
How much time will it take for an amount of Rs. 450 to yield Rs. 81 as interest at 4.5% per annum of simple interest ?
Nirav and Mehul borrowed Rs.4000 and Rs.5000 respectively for 2.5 years at the rate of x% per annum. Mehul paid Rs 125 more interest than Nirav. Find x.
If the interest on a sum of Rs.1200 is more than the interest on Rs.1000 by Rs.120 in three years, then what is the rate of interest per annum?.
The difference between the simple interest received from two banks on Rs. 500 for two years is Rs. 2.50. What is the difference between their rates?
A sum of Rs.1200 becomes Rs.1560 at a rate of simple interest in 3 years. In how many years will the sum of Rs.800 amount to Rs.1120 at the same rate of simple interest?