The problem asks for the annual simple interest rate (R) when an initial amount (Principal, P) grows to a new amount (A) in a given time (T).
The Simple Interest earned is the difference between the final Amount and the Principal:
$ SI = A - P $
Substituting the value of A:
$ SI = \frac{8}{5}P - P $
To subtract, find a common denominator:
$ SI = \frac{8}{5}P - \frac{5}{5}P $
$ SI = \frac{8 - 5}{5}P $
$ SI = \frac{3}{5}P $
The formula for Simple Interest is:
$ SI = \frac{P \times R \times T}{100} $
We know SI = $\frac{3}{5}P$ and T = 5 years. Substitute these values into the formula:
$ \frac{3}{5}P = \frac{P \times R \times 5}{100} $
We can cancel out P from both sides of the equation (assuming P is not zero):
$ \frac{3}{5} = \frac{R \times 5}{100} $
Now, solve for R. First, simplify the right side:
$ \frac{3}{5} = \frac{5R}{100} $
Multiply both sides by 100 to isolate 5R:
$ \frac{3}{5} \times 100 = 5R $
$ 3 \times 20 = 5R $
$ 60 = 5R $
Divide by 5 to find R:
$ R = \frac{60}{5} $
$ R = 12 $
Therefore, the simple interest rate is 12% per annum.
How much time will it take for an amount of Rs. 450 to yield Rs. 81 as interest at 4.5% per annum of simple interest ?
Nirav and Mehul borrowed Rs.4000 and Rs.5000 respectively for 2.5 years at the rate of x% per annum. Mehul paid Rs 125 more interest than Nirav. Find x.
The difference between the simple interest received from two banks on Rs. 500 for two years is Rs. 2.50. What is the difference between their rates?
P borrowed an amount from Q at a simple interest of 10% p.a. At the end of the year, P paid back Rs 99000 which was 90% of what she owed. How much money did P borrow?
An amount becomes Rs. 3795 in 3 years and Rs. 4537.50 in \(7 \frac{1}{2}\) years on simple interest. Find the rate of interest per annum.