To determine which mixture has a greater concentration of syrup, we need to calculate the concentration for each mixture.
Calculate Syrup Concentration for Mixture A
Mixture A contains 5 L of syrup and 6 L of water.
- Total volume of Mixture A = Volume of Syrup + Volume of Water
- Total volume of Mixture A = 5 L + 6 L = 11 L
- Concentration of syrup in A = $ \frac{\text{Volume of Syrup}}{\text{Total Volume}} \times 100\% $
- Concentration of syrup in A = $ \frac{5 \text{ L}}{11 \text{ L}} \times 100\% \approx 45.45\% $
Calculate Syrup Concentration for Mixture B
Mixture B contains 3.5 L of syrup and 5.5 L of water.
- Total volume of Mixture B = Volume of Syrup + Volume of Water
- Total volume of Mixture B = 3.5 L + 5.5 L = 9 L
- Concentration of syrup in B = $ \frac{\text{Volume of Syrup}}{\text{Total Volume}} \times 100\% $
- Concentration of syrup in B = $ \frac{3.5 \text{ L}}{9 \text{ L}} \times 100\% \approx 38.89\% $
Compare Concentrations and Conclude
Comparing the concentrations:
- Mixture A concentration ≈ 45.45%
- Mixture B concentration ≈ 38.89%
Since 45.45% is greater than 38.89%, the concentration of syrup is greater in Mixture A.
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Important Questions from Mixture and Alligation
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If 1 litre of water weighs 1 kg, then how many cubic millimeters of water will weigh 0.1 gm?
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