This problem involves calculating the amount of water to add to a milk-water mixture to achieve a specific new ratio.
The initial mixture has a total volume of 120 litres with a milk to water ratio of $2:1$.
The goal is to change the ratio to $1:2$ (Milk:Water) by adding only water. The amount of milk remains constant at 80 litres.
Let the amount of water added be $x$ litres.
The new amount of water will be $(40 + x)$ litres.
The new ratio equation is:
$ \frac{\text{Milk}}{\text{New Water}} = \frac{80}{40 + x} $We need this ratio to be $1:2$. So:
$ \frac{80}{40 + x} = \frac{1}{2} $Cross-multiply to solve for $x$:
$ 80 \times 2 = 1 \times (40 + x) $ $ 160 = 40 + x $ $ x = 160 - 40 $ $ x = 120 \text{ litres} $To achieve the desired milk to water ratio of $1:2$, 120 litres of water must be added to the mixture.
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