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Question

Geeta is decorating the cover of her school magazine. She is allowed to use only three colours from a group of six colours (P, Q, R, S, T and U), based on the following conditions.
I. If P, Q or R is chosen, U cannot be chosen.
II. Either T or U must be chosen.
III. S and Q cannot be chosen together.
If R is chosen, which of the following pairs of colours must also be chosen?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
TS

The problem asks to identify a pair of colors that must be chosen along with color 'R', given a set of conditions for selecting 3 colors from {P, Q, R, S, T, U}. The final selection must contain exactly 3 colors.

Analyzing the Conditions with R Chosen

  1. Premise: Color R is chosen.
  2. Condition I Analysis: Condition I states "If P, Q or R is chosen, U cannot be chosen". Since R is chosen, color U cannot be part of the selection.

    Formal representation: $R \implies \neg U$

  3. Condition II Analysis: Condition II states "Either T or U must be chosen". We know from the previous step that U is not chosen ($\neg U$). Therefore, T must be chosen to satisfy this condition.

    Formal representation: $(T \lor U) \land \neg U \implies T$

  4. Current Selection: Based on the premise and Conditions I & II, the selection must include both R and T. The set is currently {R, T, _}. We need one more color.
  5. Identifying the Third Color: The available colors are {P, Q, R, S, T, U}. We have already chosen R and T. U is ruled out. So, the third color must be chosen from the remaining options {P, Q, S}.
  6. Condition III Analysis: Condition III states "S and Q cannot be chosen together". This means we cannot select both S and Q in the final set of 3 colors.

    Formal representation: $\neg (S \land Q)$

  7. Evaluating Possible Combinations:
    • Case 1: Choose P as the third color. Set = {R, T, P}. This is valid as it satisfies all conditions (R chosen, U not chosen; T chosen; S and Q not together).
    • Case 2: Choose Q as the third color. Set = {R, T, Q}. This is valid (R chosen, U not chosen; T chosen; S and Q not together as S is absent).
    • Case 3: Choose S as the third color. Set = {R, T, S}. This is valid (R chosen, U not chosen; T chosen; S and Q not together as Q is absent).

Evaluating the Options

The question asks which *pair* must *also* be chosen. This implies the pair, along with R, forms the required set of 3 colors.

  • Option 1 (QS): Requires the set {R, Q, S}. This violates Condition III (S and Q cannot be chosen together).
  • Option 2 (TS): Requires the set {R, T, S}. We confirmed this is a valid combination in step 7, Case 3.
  • Option 3 (PU): Requires the set {R, P, U}. This violates Condition I (U cannot be chosen if R is chosen).
  • Option 4 (US): Requires the set {R, U, S}. This violates Condition I (U cannot be chosen if R is chosen).

Only Option 2 (TS) results in a valid combination ({R, T, S}) when considered as the required pair along with R. Although T is guaranteed, S is not strictly guaranteed as P or Q could be chosen instead. However, among the given options, TS is the only pair that forms a valid potential combination ({R, T, S}) satisfying all rules when R is initially chosen, while other options lead to direct violations of the conditions.

Conclusion

Given that R is chosen, U cannot be chosen (Condition I), which forces T to be chosen (Condition II). Thus, R and T must be selected. Evaluating the options, only the pair TS, when combined with R, forms a valid selection ({R, T, S}) consistent with all given conditions. The other options lead to contradictions.

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