Let $T$ represent the total stock (in kg) at the beginning.
Initially, product A constituted 80% of the total stock.
Following the removal of specific quantities:
The quantities remaining in the stock are:
The ratio of the final quantities of Product A to Product B is given as 9 : 2.
We can express this relationship as an equation:
$ \frac{A_{final}}{B_{final}} = \frac{9}{2} $Substituting the expressions for $A_{final}$ and $B_{final}$:
$ \frac{0.80T - 20}{0.20T - 8} = \frac{9}{2} $To find $T$, we solve the equation:
Cross-multiply the terms:
$ 2 \times (0.80T - 20) = 9 \times (0.20T - 8) $ $ 1.60T - 40 = 1.80T - 72 $Rearrange the equation to isolate $T$:
$ 72 - 40 = 1.80T - 1.60T $ $ 32 = 0.20T $Calculate the value of $T$:
$ T = \frac{32}{0.20} $ $ T = \frac{320}{2} $ $ T = 160 $The total stock in the beginning was 160 kg.
My father is presently 25 years older than me. The sum of our ages 5 years ago was 39 years. Find my present age.
Rice worth ₹43/kg and ₹67/kg are mixed with a third variety in the ratio 2 : 1 : 5. If the mixture is worth ₹96/kg, the price (in ₹) of the third variety of rice per kg will be:
42 litres of milk at ₹25 per litre is mixed with 28 litres of milk at ₹40 per litre. Find the average price of the mixture.
15 kg of ₹10 per kg wheat is mixed with 5 kg of another type of wheat to get a mixture costing ₹30 per kg. Find the price (per kg) of the costlier wheat.
If a + b + c = 0, then the value of (a² + b² + 2ab) is equal to: