This problem involves calculating the ratio of milk and water in a second container (Container B) based on how its contents are mixed with another container (Container A) to achieve a specific final mixture ratio.
We are given the ratio of milk to water in two containers:
The mixtures from Container A and Container B are mixed in the ratio 2:3. The total final volume is 20 litres.
The final 20-litre mixture has a milk to water ratio of 3:7.
We can find the amount of milk contributed by Container B by subtracting the milk from Container A from the total milk in the final mixture.
We know that 12 litres of mixture were taken from Container B, and this contained 4 litres of milk. The fraction of milk in Container B is \(\frac{m}{m+n}\).
Now, we solve for \(\frac{m}{n}\):
Alternatively, we could calculate using water:
Both methods confirm the result.
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