In a class, there are 25 students whose average age decreases by 3 months when one student aged 22 years is replaced by a new student. The age of
the new student is:
15 Yrs 9 months
This problem requires us to determine the age of a new student based on how the average age of a class changes when one student is replaced. We know the total number of students, the amount the average age changed, and the age of the student who was replaced.
Here's a breakdown of the key information given:
25 students.Let \(n\) represent the number of students in the class. We are given \(n = 25\). Let \(\Delta \bar{x}\) represent the change in the average age. Since the average age decreases by 3 months, \(\Delta \bar{x} = -3\) months.
Let \(Age_{old}\) be the age of the student who was replaced, and \(Age_{new}\) be the age of the new student.
The age of the student who left is given as \(Age_{old} = 22\) years.
To perform calculations consistently, let's convert the age of the old student entirely into months:
\[ Age_{old} = 22 \text{ years} \times 12 \text{ months/year} = 264 \text{ months} \]
The relationship between the change in average age and the total change in the sum of ages is:
\[ \Delta \bar{x} = \frac{\text{Sum of Ages}_{new} - \text{Sum of Ages}_{old}}{n} \]
The change in the sum of ages is solely due to the replacement of one student. Thus:
\[ \text{Sum of Ages}_{new} - \text{Sum of Ages}_{old} = Age_{new} - Age_{old} \]
Substituting this into the formula for the change in average age:
\[ \Delta \bar{x} = \frac{Age_{new} - Age_{old}}{n} \]
We can rearrange this to find the total change in the sum of ages:
\[ \text{Total Change in Sum of Ages} = n \times \Delta \bar{x} \]
Plugging in the known values:
\[ \text{Total Change in Sum of Ages} = 25 \times (-3 \text{ months}) = -75 \text{ months} \]
This means the sum of the ages of all students decreased by 75 months. We also know this total change equals \(Age_{new} - Age_{old}\). So:
\[ Age_{new} - Age_{old} = -75 \text{ months} \]
Now substitute the value of \(Age_{old}\) in months:
\[ Age_{new} - 264 \text{ months} = -75 \text{ months} \]
To find the age of the new student, we solve for \(Age_{new}\):
\[ Age_{new} = 264 \text{ months} - 75 \text{ months} \]
\[ Age_{new} = 189 \text{ months} \]
The final step is to convert this age back into years and months. We divide 189 by 12 (the number of months in a year):
\[ \text{Years} = \left\lfloor \frac{189}{12} \right\rfloor = 15 \]
\[ \text{Remaining Months} = 189 \pmod{12} = 9 \]
So, the age of the new student is 15 years and 9 months.
The age of the new student is 15 years 9 months.
The average of 25 numbers is 36. If the average of first 13 numbers is 32 and that of the last 13 numbers is 39, then the 13th number is
The mode (correct to two decimal places) for the given data is:
Class- interval | Frequency |
0-10 | 6 |
10-20 | 9 |
20-30 | 8 |
30-40 | 14 |
40-50 | 28 |
50-60 | 20 |
60-70 | 11 |
70-80 | 9 |
The arithmetic mean of marks of the students for the given data is:
Marks | No. of students |
0-10 | 12 |
10-20 | 18 |
20-30 | 27 |
30-40 | 20 |
40-50 | 17 |
50-60 | 60 |
The incomes of the employees in a state is assumed to be normally distributed with mean Rs.15,000 and variance Rs. 900. The median of the distribution of the income is:
For a moderately skewed distribution, let mode = 15, median = 17.4. The value of mean is:
For the data set with the following observations, the first and second quartiles are:
20, 22, 23, 22, 23, 22, 22, 21, 19, 22, 22, 26, 23, 24, 19, 21, 22, 16
For an asymmetric distribution, if the mean and median are 20 and 30, then the value of the mode is:
For a data set with 24 observations given below, the median is:
10, 11, 13, 13, 18, 20, 22, 22, 24, 24, 25, 29, 30, 31, 35, 37, 37, 37, 46, 51, 54, 55, 61, 64
There are 35 students in a hostel. If the number of students increases by 7, the expenses of the hostel increases by Rs. 42 per day while the average
expenditure per head diminishes by Re. 1. The original expenditure of the hostel is:
If \(P=\dfrac{\sum^n_{i=1}(x_i-A)^2}{\sum^n_{i=1}(x_i-\bar x)^2};A\ne\bar x,\) (x̅ = Arithmetic Mean) then P is:
A random sample of 20 people is classified in the following table according to their ages:
Age | Frequency |
15 – 25 | 2 |
25 – 35 | 4 |
35 – 45 | 6 |
45 – 55 | 5 |
55 - 65 | 3 |
What is the mean age of this group of people?
If the difference of mode and median is 36, then the difference of median and mean is:
In a Mathematics test 15 students scored 80 marks, 20 students scored 75 marks, 28 students scored 65 marks and 25 students scored 60 marks, mode of the score is:
If the mode of the scores 10, 12, 13, 15, 15, 13, 12, 10, x is 15, then what is the value of x?
The average of 25 numbers is 36. If the average of first 13 numbers is 32 and that of the last 13 numbers is 39, then the 13th number is