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Question

For the frequency distribution of income (in lakh) of the employees in factory

Class:1.5-2.52.5-3.53.5-4.54.5-5.5
Frequency:1342

the value of mode is

This question was previously asked in
SSC CGL 2020 (Tier-2) Statistics Previous Year Paper 3 (28-Jan-2022)
The correct answer is

3.833

Calculating the Mode of a Frequency Distribution of Income

The question asks us to find the mode for a given frequency distribution representing the income (in lakh) of employees in a factory.

A frequency distribution organizes data by grouping it into classes and showing how often each group appears. The mode is the value that appears most frequently in a dataset. For a grouped frequency distribution, the mode is estimated using a specific formula, after identifying the modal class.

Understanding the Given Data

The provided data is a frequency distribution table:

Class (Income in Lakh) Frequency (Number of Employees)
1.5-2.5 1
2.5-3.5 3
3.5-4.5 4
4.5-5.5 2

Identifying the Modal Class

The modal class is the class interval with the highest frequency. Looking at the frequencies (1, 3, 4, 2), the highest frequency is 4. This corresponds to the class interval 3.5-4.5.

So, the modal class is 3.5-4.5.

Formula for Mode of Grouped Data

The formula used to calculate the mode (\(M_o\)) for a grouped frequency distribution is:

\(M_o = L + \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \times h\)

Where:

  • \(L\) = Lower limit of the modal class
  • \(f_1\) = Frequency of the modal class
  • \(f_0\) = Frequency of the class preceding the modal class
  • \(f_2\) = Frequency of the class succeeding the modal class
  • \(h\) = Class width (size) of the modal class

Applying the Formula to Find the Mode

From our identified modal class (3.5-4.5) and the frequency distribution:

  • \(L\) = Lower limit of the modal class = 3.5
  • \(f_1\) = Frequency of the modal class (3.5-4.5) = 4
  • \(f_0\) = Frequency of the class preceding the modal class (2.5-3.5) = 3
  • \(f_2\) = Frequency of the class succeeding the modal class (4.5-5.5) = 2
  • \(h\) = Class width = Upper limit - Lower limit = 4.5 - 3.5 = 1

Now, substitute these values into the mode formula:

\(M_o = 3.5 + \frac{4 - 3}{2(4) - 3 - 2} \times 1\)

Calculate the terms:

\(M_o = 3.5 + \frac{1}{8 - 3 - 2} \times 1\)

\(M_o = 3.5 + \frac{1}{3} \times 1\)

\(M_o = 3.5 + 0.3333...\)

\(M_o \approx 3.833\)

Conclusion

The calculated value for the mode of the income distribution is approximately 3.833 lakh.

Revision Table: Key Concepts for Mode Calculation

Concept Description How it applies here
Frequency Distribution A table showing the frequency of observations within specific intervals or categories. The given data organizes employee income into classes with corresponding frequencies.
Mode The value that appears most frequently in a dataset. For grouped data, it's an estimate. We are calculating the mode for the income data.
Modal Class The class interval with the highest frequency. Identified as 3.5-4.5 because it has the highest frequency (4).
Mode Formula (Grouped Data) \(M_o = L + \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \times h\) The formula used to estimate the mode from the modal class and adjacent frequencies.

Additional Information: Measures of Central Tendency

Mode is one of the three main measures of central tendency used to describe the center of a dataset. The others are Mean and Median.

  • Mean: The average of all observations. Calculated by summing all values and dividing by the number of observations. For grouped data, it involves using class midpoints.
  • Median: The middle value in a dataset when arranged in order. For grouped data, it is calculated using a formula after finding the median class (the class containing the \((n/2)\)-th observation).
  • Mode: Represents the most frequent value or class. Useful for categorical data or identifying peaks in distributions.

These measures provide different perspectives on the central typical value of the income distribution.

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Similar Questions

  1. For a moderately skewed distribution, let mode = 15, median = 17.4. The value of mean is:

  2. For the data set with the following observations, the first and second quartiles are:

    20, 22, 23, 22, 23, 22, 22, 21, 19, 22, 22, 26, 23, 24, 19, 21, 22, 16

  3. For a data set with 24 observations given below, the median is:

    10, 11, 13, 13, 18, 20, 22, 22, 24, 24, 25, 29, 30, 31, 35, 37, 37, 37, 46, 51, 54, 55, 61, 64

  4. In a class of 15 students, 5 fail in a test. Marks of remaining 10 students are 9, 6, 8, 7, 8, 9, 5, 6, 7 and 4. The median of marks of all 15 students is:

  5. For normal distribution, which of the following is true?  

  6. If the median of the observations 2, 3, 5, 6, x, 8, 9, is 6 then x CANNOT be equal to:

  7. The mean and median of the distribution is 12 and 15. Then the mode equals to:

  8. If the first quartile of data set 8, 10, 8, 7, 9 is 7.5, then the value of quartile deviation is

  9. If the third quartile of the following data set 7, 10, 7, 8, 9 is 9.5, then the value of quartile deviation is:

  10. The median of the following observations 10, 11, 9, 12, 10, 10, 12, 10, 9, 11 is:


Important Questions from Measures of Central Tendency

  1. What is mean deviation about the median ?

  2. The mode and median of a data is 26.7 and 71, respectively. What is the mean of the data? (Use empirical formula.)

  3. Study the given table and answer the question that follows. The given table depicts the percentage of marks scored by Mary and Perul in History and Physics (out of 75 each).

                        Name                                         History                                       Physics                       

    Mary

    60

    64

    Perul

    54

    70

    How many marks did Mary score in History?

  4. The average of eight numbers is 14. The average of six of these numbers is 16. The average of the remaining two numbers is:

  5. The value of

    (1 + cot²θ)(1 + cosθ)(1 - cosθ) - (1 - sinθ)(1 + sinθ)(1 + tan²θ) is: (θ lies in the first quadrant)

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