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Question

The incomes of the employees in a state is assumed to be normally distributed with mean Rs.15,000 and variance Rs. 900. The median of the distribution of the income is:

This question was previously asked in
SSC CGL 2018 (Tier 2) Statistics Previous Year Paper (22-feb-2018)
The correct answer is

Rs.15,000

The normal distribution is perfectly symmetric about its mean, so mean = median = mode. The median therefore equals the given mean.

Mean = Rs. 15,000, hence Median = Rs. 15,000. The variance (900) controls spread but does not shift the centre.

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Similar Questions

  1. The average of 25 numbers is 36. If the average of first 13 numbers is 32 and that of the last 13 numbers is 39, then the 13th number is

  2. The mode (correct to two decimal places) for the given data is:

    Class-   interval

    Frequency

     0-10

     6 

     10-20

     9

     20-30

     8

     30-40

     14

     40-50

     28

     50-60

     20

     60-70

     11

     70-80

     9

  3. The arithmetic mean of marks of the students for the given data is:

    Marks

    No. of students

    0-10

    12

    10-20

    18

    20-30

    27

    30-40

    20

    40-50

    17

    50-60

    60

  4. For a moderately skewed distribution, let mode = 15, median = 17.4. The value of mean is:

  5. For the data set with the following observations, the first and second quartiles are:

    20, 22, 23, 22, 23, 22, 22, 21, 19, 22, 22, 26, 23, 24, 19, 21, 22, 16

  6. For an asymmetric distribution, if the mean and median are 20 and 30, then the value of the mode is:

  7. For a data set with 24 observations given below, the median is:

    10, 11, 13, 13, 18, 20, 22, 22, 24, 24, 25, 29, 30, 31, 35, 37, 37, 37, 46, 51, 54, 55, 61, 64

  8. There are 35 students in a hostel. If the number of students increases by 7, the expenses of the hostel increases by Rs. 42 per day while the average
    expenditure per head diminishes by Re. 1. The original expenditure of the hostel is:

  9. If \(P=\dfrac{\sum^n_{i=1}(x_i-A)^2}{\sum^n_{i=1}(x_i-\bar x)^2};A\ne\bar x,\) (x̅ = Arithmetic Mean) then P is:

  10. In a class, there are 25 students whose average age decreases by 3 months when one student aged 22 years is replaced by a new student. The age of
    the new student is:


Important Questions from Measures of Central Tendency

  1. A random sample of 20 people is classified in the following table according to their ages:

    Age

    Frequency

    15 – 25

    2

    25 – 35

    4

    35 – 45

    6

    45 – 55

    5

    55 - 65

    3

    What is the mean age of this group of people?

  2. If the difference of mode and median is 36, then the difference of median and mean is:

  3. In a Mathematics test 15 students scored 80 marks, 20 students scored 75 marks, 28 students scored 65 marks and 25 students scored 60 marks, mode of the score is:

  4. If the mode of the scores 10, 12, 13, 15, 15, 13, 12, 10, x is 15, then what is the value of x?

  5. The average of 25 numbers is 36. If the average of first 13 numbers is 32 and that of the last 13 numbers is 39, then the 13th number is

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