Calculate the mode of the following frequency distribution Seconds 51-55 56-60 61-65 66-70 Frequency 2 7 8 4
61.5
The mode is a measure of central tendency that represents the most frequently occurring value in a dataset. For a grouped frequency distribution, the mode falls within the class interval that has the highest frequency, known as the modal class.
Let's look at the given frequency distribution:
| Seconds | Frequency |
|---|---|
| 51-55 | 2 |
| 56-60 | 7 |
| 61-65 | 8 |
| 66-70 | 4 |
From the table, we can see that the highest frequency is 8, which corresponds to the class interval 61-65. Therefore, the modal class is 61-65.
The formula used to calculate the mode for a grouped frequency distribution is:
\[ \text{Mode} = L + \left(\frac{f_1 - f_0}{2f_1 - f_0 - f_2}\right) \times h \]Where:
Based on the modal class 61-65 and the frequency distribution:
To find the lower boundary (\(L\)) and class size (\(h\)), we need to consider the class intervals. The intervals are 51-55, 56-60, 61-65, 66-70. There is a gap of 1 between the upper limit of one class and the lower limit of the next (e.g., 55 to 56, 60 to 61). To make the classes continuous, we adjust the boundaries by subtracting 0.5 from the lower limit and adding 0.5 to the upper limit.
Now, we substitute the values into the mode formula:
\[ L = 60.5 \] \[ f_1 = 8 \] \[ f_0 = 7 \] \[ f_2 = 4 \] \[ h = 5 \] \[ \text{Mode} = 60.5 + \left(\frac{8 - 7}{2(8) - 7 - 4}\right) \times 5 \] \[ \text{Mode} = 60.5 + \left(\frac{1}{16 - 7 - 4}\right) \times 5 \] \[ \text{Mode} = 60.5 + \left(\frac{1}{16 - 11}\right) \times 5 \] \[ \text{Mode} = 60.5 + \left(\frac{1}{5}\right) \times 5 \] \[ \text{Mode} = 60.5 + 1 \] \[ \text{Mode} = 61.5 \]The calculated mode of the frequency distribution is 61.5.
| Term | Definition/Meaning in Calculation |
|---|---|
| Mode | The value that appears most frequently in a data set. For grouped data, it's the peak of the distribution. |
| Modal Class | The class interval with the highest frequency. |
| Lower Boundary (\(L\)) | The actual lower limit of the modal class, adjusted for continuity (usually by subtracting 0.5 from the listed lower limit if there are gaps between classes). |
| Frequency (\(f\)) | The number of observations within a specific class interval. |
| \(f_1\) | Frequency of the modal class. |
| \(f_0\) | Frequency of the class immediately preceding the modal class. |
| \(f_2\) | Frequency of the class immediately succeeding the modal class. |
| Class Size (\(h\)) | The width of the class interval (difference between upper and lower boundaries). |
The mode is one of the three main measures of central tendency, alongside the mean and the median. Each measure provides a different perspective on the center of a dataset:
For grouped frequency distributions, the calculation methods for mean, median, and mode are slightly different from ungrouped data, involving class intervals and frequencies.
The average of 25 numbers is 36. If the average of first 13 numbers is 32 and that of the last 13 numbers is 39, then the 13th number is
The approximate harmonic mean of 8, 6, 12, 4 is:
The mode (correct to two decimal places) for the given data is:
Class- interval | Frequency |
0-10 | 6 |
10-20 | 9 |
20-30 | 8 |
30-40 | 14 |
40-50 | 28 |
50-60 | 20 |
60-70 | 11 |
70-80 | 9 |
The arithmetic mean of marks of the students for the given data is:
Marks | No. of students |
0-10 | 12 |
10-20 | 18 |
20-30 | 27 |
30-40 | 20 |
40-50 | 17 |
50-60 | 60 |
The incomes of the employees in a state is assumed to be normally distributed with mean Rs.15,000 and variance Rs. 900. The median of the distribution of the income is:
If the median of the observations 2, 3, 5, 6, x, 8, 9, is 6 then x CANNOT be equal to:
For a moderately skewed distribution, let mode = 15, median = 17.4. The value of mean is:
For the data set with the following observations, the first and second quartiles are:
20, 22, 23, 22, 23, 22, 22, 21, 19, 22, 22, 26, 23, 24, 19, 21, 22, 16
For an asymmetric distribution, if the mean and median are 20 and 30, then the value of the mode is:
For a data set with 24 observations given below, the median is:
10, 11, 13, 13, 18, 20, 22, 22, 24, 24, 25, 29, 30, 31, 35, 37, 37, 37, 46, 51, 54, 55, 61, 64
A random sample of 20 people is classified in the following table according to their ages:
Age | Frequency |
15 – 25 | 2 |
25 – 35 | 4 |
35 – 45 | 6 |
45 – 55 | 5 |
55 - 65 | 3 |
What is the mean age of this group of people?
The median of the following observations 46, 64, 87, 41, 58, 77, 35, 90, 55, 92, 33 is 58. If 92 is replaced by 99 and 41 by 43 in the above data. The new median is:
If the difference of mode and median is 36, then the difference of median and mean is:
In a Mathematics test 15 students scored 80 marks, 20 students scored 75 marks, 28 students scored 65 marks and 25 students scored 60 marks, mode of the score is:
If the mode of the scores 10, 12, 13, 15, 15, 13, 12, 10, x is 15, then what is the value of x?