If the third quartile of the following data set 7, 10, 7, 8, 9 is 9.5, then the value of quartile deviation is:
1.25
The question asks us to calculate the quartile deviation for a given data set, where the third quartile is already provided. Quartile deviation is a measure of dispersion that describes the spread of the middle 50% of a data set. It is half the difference between the third quartile ($Q_3$) and the first quartile ($Q_1$).
To find the quartile deviation, we need to determine the values of the first quartile ($Q_1$) and the third quartile ($Q_3$). The formula for quartile deviation (QD) is:
$$QD = \frac{Q_3 - Q_1}{2}$$
We are given the data set: 7, 10, 7, 8, 9 and the third quartile, $Q_3 = 9.5$. We need to find the first quartile, $Q_1$, from the data set.
First, let's arrange the data set in ascending order:
The ordered data set is 7, 7, 8, 9, 10. There are $n=5$ data points.
The first quartile ($Q_1$) is the value at the 25th percentile. For an ordered data set with $n$ observations, the position of $Q_1$ can be found using the formula: Position of $Q_1 = \frac{n+1}{4}$.
For this data set, $n=5$.
Position of $Q_1 = \frac{5+1}{4} = \frac{6}{4} = 1.5$$
This means $Q_1$ is located halfway between the 1st and 2nd values in the ordered data set.
The 1st value is 7.
The 2nd value is 7.
$$Q_1 = \frac{\text{1st value} + \text{2nd value}}{2} = \frac{7+7}{2} = \frac{14}{2} = 7$$
So, the first quartile is $Q_1 = 7$.
The third quartile ($Q_3$) is the value at the 75th percentile. The position of $Q_3$ can be found using the formula: Position of $Q_3 = \frac{3(n+1)}{4}$.
For this data set, $n=5$.
Position of $Q_3 = \frac{3(5+1)}{4} = \frac{3 \times 6}{4} = \frac{18}{4} = 4.5$$
This means $Q_3$ is located halfway between the 4th and 5th values in the ordered data set.
The 4th value is 9.
The 5th value is 10.
$$Q_3 = \frac{\text{4th value} + \text{5th value}}{2} = \frac{9+10}{2} = \frac{19}{2} = 9.5$$
The calculated $Q_3$ is 9.5, which matches the value given in the question.
Now that we have $Q_1 = 7$ and $Q_3 = 9.5$, we can calculate the quartile deviation using the formula:
$$QD = \frac{Q_3 - Q_1}{2}$$
$$QD = \frac{9.5 - 7}{2} = \frac{2.5}{2} = 1.25$$
Thus, the quartile deviation is 1.25.
| Statistic | Value |
|---|---|
| Data Set (Ordered) | 7, 7, 8, 9, 10 |
| Number of observations (n) | 5 |
| First Quartile ($Q_1$) | 7 |
| Third Quartile ($Q_3$) | 9.5 |
| Quartile Deviation (QD) | 1.25 |
Based on the calculations, the first quartile ($Q_1$) is 7 and the third quartile ($Q_3$) is 9.5. Using these values, the quartile deviation is 1.25.
| Concept | Description | Formula/Calculation |
|---|---|---|
| Quartiles | Values that divide a data set into four equal parts. | $Q_1$ (25th percentile), $Q_2$ (50th percentile or median), $Q_3$ (75th percentile) |
| First Quartile ($Q_1$) | The median of the lower half of the data set. | Position: $\frac{n+1}{4}$-th value in ordered data. |
| Third Quartile ($Q_3$) | The median of the upper half of the data set. | Position: $\frac{3(n+1)}{4}$-th value in ordered data. |
| Interquartile Range (IQR) | The range of the middle 50% of the data. | $IQR = Q_3 - Q_1$ |
| Quartile Deviation (QD) | Half of the interquartile range. Measure of dispersion. | $QD = \frac{Q_3 - Q_1}{2}$ |
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