The median of the following observations 10, 11, 9, 12, 10, 10, 12, 10, 9, 11 is:
10
The question asks us to find the median of a given set of observations: 10, 11, 9, 12, 10, 10, 12, 10, 9, 11.
The median is a measure of central tendency. It is the middle value in a data set that is arranged in ascending or descending order. The median divides the data set into two equal halves.
To find the median of a set of observations, follow these steps:
Let's apply these steps to the observations: 10, 11, 9, 12, 10, 10, 12, 10, 9, 11.
Step 1: Arrange in Ascending Order
Arranging the observations in ascending order, we get:
9, 9, 10, 10, 10, 10, 11, 11, 12, 12
Step 2: Count the Number of Observations (n)
Let's count the number of observations in the set:
9, 9, 10, 10, 10, 10, 11, 11, 12, 12
There are 10 observations. So, n = 10.
Step 3: Determine if n is Odd or Even
Since n = 10, which is an even number.
Step 4: Calculate the Median for Even n
For an even number of observations, the median is the average of the observations at the \(\left(\frac{n}{2}\right)^{\text{th}}\) position and the \(\left(\frac{n}{2} + 1\right)^{\text{th}}\) position.
Looking at the sorted observations (9, 9, 10, 10, 10, 10, 11, 11, 12, 12):
Now, we calculate the average of the 5th and 6th observations:
Median = \(\frac{\text{5}^{\text{th}}\text{ observation} + \text{6}^{\text{th}}\text{ observation}}{2}\)
Median = \(\frac{10 + 10}{2}\)
Median = \(\frac{20}{2}\)
Median = 10
The median of the given observations 10, 11, 9, 12, 10, 10, 12, 10, 9, 11 is 10.
| Position | Sorted Observation |
|---|---|
| 1 | 9 |
| 2 | 9 |
| 3 | 10 |
| 4 | 10 |
| 5 | 10 |
| 6 | 10 |
| 7 | 11 |
| 8 | 11 |
| 9 | 12 |
| 10 | 12 |
| Step | Action | Observation for this Problem |
|---|---|---|
| 1 | Arrange data in ascending order | 9, 9, 10, 10, 10, 10, 11, 11, 12, 12 |
| 2 | Count number of observations (n) | n = 10 |
| 3 | Check if n is odd or even | n = 10 (Even) |
| 4a | If n is odd, find \(\left(\frac{n+1}{2}\right)^{\text{th}}\) term | N/A (n is even) |
| 4b | If n is even, find average of \(\left(\frac{n}{2}\right)^{\text{th}}\) and \(\left(\frac{n}{2}+1\right)^{\text{th}}\) terms | \(\frac{\text{5}^{\text{th}} + \text{6}^{\text{th}}}{2} = \frac{10+10}{2} = 10\) |
The median is one of the main measures of central tendency, which are used to describe the center point of a data set. Other common measures include:
The choice of which measure of central tendency to use depends on the nature of the data and the presence of outliers. The median is often preferred over the mean for skewed data or data with outliers, as it is less affected by extreme values.
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