All Exams Test series for 1 year @ ₹349 only
Question

The median of the following observations 10, 11, 9, 12, 10, 10, 12, 10, 9, 11 is:

This question was previously asked in
SSC CGL 2020 (Tier-2) Statistics Previous Year Paper 3 (28-Jan-2022)
The correct answer is

10

Finding the Median of Observations

The question asks us to find the median of a given set of observations: 10, 11, 9, 12, 10, 10, 12, 10, 9, 11.

Understanding the Median

The median is a measure of central tendency. It is the middle value in a data set that is arranged in ascending or descending order. The median divides the data set into two equal halves.

Steps to Calculate the Median

To find the median of a set of observations, follow these steps:

  1. Arrange the observations in ascending order (from smallest to largest).
  2. Count the total number of observations, denoted by 'n'.
  3. Determine if 'n' is an odd or even number.
  4. If 'n' is odd, the median is the observation at the \(\left(\frac{n+1}{2}\right)^{\text{th}}\) position.
  5. If 'n' is even, the median is the average of the observations at the \(\left(\frac{n}{2}\right)^{\text{th}}\) position and the \(\left(\frac{n}{2} + 1\right)^{\text{th}}\) position.

Applying the Steps to the Given Observations

Let's apply these steps to the observations: 10, 11, 9, 12, 10, 10, 12, 10, 9, 11.

Step 1: Arrange in Ascending Order

Arranging the observations in ascending order, we get:

9, 9, 10, 10, 10, 10, 11, 11, 12, 12

Step 2: Count the Number of Observations (n)

Let's count the number of observations in the set:

9, 9, 10, 10, 10, 10, 11, 11, 12, 12

There are 10 observations. So, n = 10.

Step 3: Determine if n is Odd or Even

Since n = 10, which is an even number.

Step 4: Calculate the Median for Even n

For an even number of observations, the median is the average of the observations at the \(\left(\frac{n}{2}\right)^{\text{th}}\) position and the \(\left(\frac{n}{2} + 1\right)^{\text{th}}\) position.

  • The \(\left(\frac{n}{2}\right)^{\text{th}}\) position is the \(\left(\frac{10}{2}\right)^{\text{th}} = 5^{\text{th}}\) position.
  • The \(\left(\frac{n}{2} + 1\right)^{\text{th}}\) position is the \(\left(\frac{10}{2} + 1\right)^{\text{th}} = (5 + 1)^{\text{th}} = 6^{\text{th}}\) position.

Looking at the sorted observations (9, 9, 10, 10, 10, 10, 11, 11, 12, 12):

  • The 5th observation is 10.
  • The 6th observation is 10.

Now, we calculate the average of the 5th and 6th observations:

Median = \(\frac{\text{5}^{\text{th}}\text{ observation} + \text{6}^{\text{th}}\text{ observation}}{2}\)

Median = \(\frac{10 + 10}{2}\)

Median = \(\frac{20}{2}\)

Median = 10

Conclusion

The median of the given observations 10, 11, 9, 12, 10, 10, 12, 10, 9, 11 is 10.

Position Sorted Observation
1 9
2 9
3 10
4 10
5 10
6 10
7 11
8 11
9 12
10 12

Revision Table: Median Calculation Steps

Step Action Observation for this Problem
1 Arrange data in ascending order 9, 9, 10, 10, 10, 10, 11, 11, 12, 12
2 Count number of observations (n) n = 10
3 Check if n is odd or even n = 10 (Even)
4a If n is odd, find \(\left(\frac{n+1}{2}\right)^{\text{th}}\) term N/A (n is even)
4b If n is even, find average of \(\left(\frac{n}{2}\right)^{\text{th}}\) and \(\left(\frac{n}{2}+1\right)^{\text{th}}\) terms \(\frac{\text{5}^{\text{th}} + \text{6}^{\text{th}}}{2} = \frac{10+10}{2} = 10\)

Additional Information: Measures of Central Tendency

The median is one of the main measures of central tendency, which are used to describe the center point of a data set. Other common measures include:

  • Mean: The average of all observations. Calculated by summing all observations and dividing by the total number of observations.
  • Mode: The observation that appears most frequently in the data set. A data set can have one mode (unimodal), more than one mode (multimodal), or no mode. In the given data (9, 9, 10, 10, 10, 10, 11, 11, 12, 12), the observation 10 appears 4 times, which is more frequent than any other observation. So, the mode is 10.

The choice of which measure of central tendency to use depends on the nature of the data and the presence of outliers. The median is often preferred over the mean for skewed data or data with outliers, as it is less affected by extreme values.

Was this answer helpful?

Similar Questions

  1. The average of 25 numbers is 36. If the average of first 13 numbers is 32 and that of the last 13 numbers is 39, then the 13th number is

  2. Calculate the mode of the following frequency distribution

    Seconds

    51-55

    56-60

    61-65

    66-70

    Frequency

    2

    7

    8

    4

  3. The approximate harmonic mean of 8, 6, 12, 4 is:

  4. The mode (correct to two decimal places) for the given data is:

    Class-   interval

    Frequency

     0-10

     6 

     10-20

     9

     20-30

     8

     30-40

     14

     40-50

     28

     50-60

     20

     60-70

     11

     70-80

     9

  5. The arithmetic mean of marks of the students for the given data is:

    Marks

    No. of students

    0-10

    12

    10-20

    18

    20-30

    27

    30-40

    20

    40-50

    17

    50-60

    60

  6. The incomes of the employees in a state is assumed to be normally distributed with mean Rs.15,000 and variance Rs. 900. The median of the distribution of the income is:

  7. For a moderately skewed distribution, let mode = 15, median = 17.4. The value of mean is:

  8. For the data set with the following observations, the first and second quartiles are:

    20, 22, 23, 22, 23, 22, 22, 21, 19, 22, 22, 26, 23, 24, 19, 21, 22, 16

  9. For an asymmetric distribution, if the mean and median are 20 and 30, then the value of the mode is:

  10. For a data set with 24 observations given below, the median is:

    10, 11, 13, 13, 18, 20, 22, 22, 24, 24, 25, 29, 30, 31, 35, 37, 37, 37, 46, 51, 54, 55, 61, 64


Important Questions from Measures of Central Tendency

  1. A random sample of 20 people is classified in the following table according to their ages:

    Age

    Frequency

    15 – 25

    2

    25 – 35

    4

    35 – 45

    6

    45 – 55

    5

    55 - 65

    3

    What is the mean age of this group of people?

  2. If the difference of mode and median is 36, then the difference of median and mean is:

  3. In a Mathematics test 15 students scored 80 marks, 20 students scored 75 marks, 28 students scored 65 marks and 25 students scored 60 marks, mode of the score is:

  4. If the mode of the scores 10, 12, 13, 15, 15, 13, 12, 10, x is 15, then what is the value of x?

  5. The average of 25 numbers is 36. If the average of first 13 numbers is 32 and that of the last 13 numbers is 39, then the 13th number is

Need Expert Advice?
Upcoming Exams
SSC JE
November 02, 2026
SSC CPO
November 23, 2026
SSC CHSL
November 30, 2026
Test Series
SSC CGL img
SSC
SSC CGL (Tier I + Tier II) 2026 Mock Test Series - Latest Pattern
2509 Tests 6 Tests Free
8792 Attempts
4.2(941)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App