What is the median of the following data?
24, 30, 40, 80, 15, 57, 78, 82, 39, 97, 82
The question asks for the median of a given set of numbers. The median is the middle value in a dataset that has been arranged in order. If there is an even number of data points, the median is the average of the two middle values.
To find the median, follow these steps:
The provided data set is: 24, 30, 40, 80, 15, 57, 78, 82, 39, 97, 82.
First, let's arrange the numbers in ascending order:
| 15 | 24 | 30 | 39 | 40 | 57 | 78 | 80 | 82 | 82 | 97 |
Let's count how many numbers are in the list. There are 11 data points. So, $n = 11$.
Since $n = 11$, which is an odd number, we use the formula for the odd case to find the position of the median: $ \text{Position} = \frac{(n + 1)}{2} $ $ \text{Position} = \frac{(11 + 1)}{2} $ $ \text{Position} = \frac{12}{2} $ $ \text{Position} = 6 $
This means the median is the 6th value in the ordered list.
Looking at the ordered list (15, 24, 30, 39, 40, 57, 78, 80, 82, 82, 97), the 6th value is 57.
Therefore, the median of the given data is 57.