In a certain code language, ‘SOLID’ is coded as ‘64’ and ‘POUR’ IS coded as ‘74’ How will ‘TON’ be coded as in that language?
52
Solving the Coding-Decoding Problem
This question involves a type of coding-decoding where words are assigned numerical values based on a specific rule. We are given the coded values for 'SOLID' and 'POUR' and need to find the code for 'TON'.
Analyzing the Coding Pattern for SOLID and POUR
Let's first examine how 'SOLID' is coded as '64' and 'POUR' is coded as '74'. We need to find a relationship between the letters of the words and the given numbers.
A common method in such problems is to use the alphabetical position of each letter (A=1, B=2, ..., Z=26).
Let's find the positional values for the letters in 'SOLID':
- S is the 19th letter.
- O is the 15th letter.
- L is the 12th letter.
- I is the 9th letter.
- D is the 4th letter.
Sum of positional values for 'SOLID':
\(19 + 15 + 12 + 9 + 4 = 59\)
The coded value is 64. The difference between the coded value and the sum of positional values is \(64 - 59 = 5\).
Notice that 'SOLID' has 5 letters.
Let's test if the rule is: Sum of positional values + Number of letters.
Now, let's apply this potential rule to 'POUR'. First, find the positional values:
- P is the 16th letter.
- O is the 15th letter.
- U is the 21st letter.
- R is the 18th letter.
Sum of positional values for 'POUR':
\(16 + 15 + 21 + 18 = 70\)
The word 'POUR' has 4 letters.
Applying the potential rule: Sum of positional values + Number of letters
\(70 + 4 = 74\)
This matches the given code for 'POUR'. Therefore, the rule is confirmed: The code for a word is the sum of the alphabetical positions of its letters plus the total number of letters in the word.
Coding the Word 'TON'
Now, let's use the discovered rule to code the word 'TON'.
First, find the positional values for the letters in 'TON':
- T is the 20th letter.
- O is the 15th letter.
- N is the 14th letter.
Sum of positional values for 'TON':
\(20 + 15 + 14 = 49\)
The word 'TON' has 3 letters.
Applying the rule: Sum of positional values + Number of letters
\(49 + 3 = 52\)
Thus, the code for 'TON' is 52.
Let's summarize the positional values for clarity:
| Letter | Alphabetical Position |
|---|---|
| S | 19 |
| O | 15 |
| L | 12 |
| I | 9 |
| D | 4 |
| P | 16 |
| U | 21 |
| R | 18 |
| T | 20 |
| N | 14 |
Final Answer Derivation
Using the rule (Sum of letter positions + Number of letters):
- For 'SOLID': \( (19+15+12+9+4) + 5 = 59 + 5 = 64 \).
- For 'POUR': \( (16+15+21+18) + 4 = 70 + 4 = 74 \).
- For 'TON': \( (20+15+14) + 3 = 49 + 3 = 52 \).
The code for 'TON' is 52.
Revision Table: Coding-Decoding Techniques
| Technique | Description | Example Rule |
|---|---|---|
| Letter Position | Using the numerical position of letters (A=1, B=26 or A=26, B=1). | Sum of positions; Product of positions; Position \(\times\) 2. |
| Number of Letters | Including the total count of letters in the calculation. | Sum of positions + number of letters; Number of letters \(\times\) a constant. |
| Vowel/Consonant Count | Using the count of vowels and consonants in the word. | (Vowel count \(\times\) X) + (Consonant count \(\times\) Y). |
| Pattern Based | Specific forward/backward shift or pairing of letters. | A coded as C, B as D (+2 shift). |
Additional Information on Letter Coding
Letter coding is a common type of question in logical reasoning sections of competitive exams. Understanding the alphabetical positions of letters is crucial. Sometimes, the reverse alphabetical order (Z=1, Y=2, ..., A=26) is used. Other variations can include multiplying or dividing the positional values, squaring them, or combining positional values with the number of letters, vowels, or consonants. Always look for a consistent pattern across the given examples before applying it to find the answer for the target word.
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