If CAB is coded as 6 and BED is coded as 40, then how will HAD be coded as?
32
This question asks us to figure out a specific coding pattern used for words and then apply it to a new word. We are given two examples:
We need to find how HAD will be coded based on this same pattern.
Let's first assign a numerical value to each letter based on its position in the English alphabet (A=1, B=2, C=3, and so on).
| Letter | Alphabetical Value |
|---|---|
| A | 1 |
| B | 2 |
| C | 3 |
| D | 4 |
| E | 5 |
| H | 8 |
Now let's look at the values for the letters in CAB and BED:
We need to find an operation (or a combination of operations) that transforms the values (3, 1, 2) into 6 and the values (2, 5, 4) into 40.
Let's try some common operations:
Since the product of the alphabetical values works for both CAB and BED, it is likely the coding pattern used in this question.
Now we will apply the identified pattern (multiplying the alphabetical values of the letters) to the word HAD.
Let's calculate the product of these values:
$8 \times 1 \times 4 = 32$
Therefore, HAD is coded as 32.
The calculated code for HAD is 32. Let's check the given options:
Our calculated value, 32, matches Option 1.
The coding logic involves assigning numerical values to letters based on their position in the alphabet (A=1, B=2, C=3, ...) and then multiplying these values together to get the code for the word.
| Word | Letters | Alphabetical Values | Operation | Coded Value |
|---|---|---|---|---|
| CAB | C, A, B | 3, 1, 2 | $3 \times 1 \times 2$ | 6 |
| BED | B, E, D | 2, 5, 4 | $2 \times 5 \times 4$ | 40 |
| HAD | H, A, D | 8, 1, 4 | $8 \times 1 \times 4$ | 32 |
Coding and decoding questions are common in reasoning and aptitude tests. They test your ability to identify patterns and rules in how information is transformed. Common types of letter coding patterns include:
Practicing different types helps you quickly identify the pattern during an exam.
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