We are asked to find the sum of the reciprocals of two numbers, given their sum and product.
Calculate the sum of the reciprocals of these two numbers, which is represented as $\frac{1}{a} + \frac{1}{b}$.
Represent the sum of reciprocals using a common denominator:
$ \frac{1}{a} + \frac{1}{b} = \frac{b}{ab} + \frac{a}{ab} = \frac{a+b}{ab} $
Substitute the given values for the sum ($a+b$) and the product ($ab$) into the expression:
$ \text{Sum of reciprocals} = \frac{30}{50} $
Simplify the resulting fraction:
$ \frac{30}{50} = \frac{3 \times 10}{5 \times 10} = \frac{3}{5} $
The sum of the reciprocals of the two numbers is $\frac{3}{5}$.
Consider the following statements :
1. (25)! + 1 is divisible by 26
2. (6)! + 1 is divisible by 7
Which of the above statements is/are correct ?
If the sum S is divided by 8, what is the remainder ?
If the sum S is divided by 60, what is the remainder ?
Find the sum of squares of the greatest value and the smallest value of K in the number so that the number 45082K is divisible by 3.
How many composite numbers are there from 53 to 97 ?