We need to find the number of factors of the number $N = 2^3 \times 3^3 \times 5^4 \times 7^2$ that satisfy two specific conditions: they must be divisible by 50, and they must not be divisible by 100.
The number is given as $N = 2^3 \times 3^3 \times 5^4 \times 7^2$.
Any factor of N has the general form $F = 2^a \times 3^b \times 5^c \times 7^d$, where the exponents are within the following ranges:
Condition 1: Divisible by 50
The prime factorization of 50 is $2^1 \times 5^2$. For a factor F to be divisible by 50, its exponents must satisfy $a \ge 1$ and $c \ge 2$.
Condition 2: Not divisible by 100
The prime factorization of 100 is $2^2 \times 5^2$. For a factor F to be divisible by 100, its exponents must satisfy $a \ge 2$ and $c \ge 2$. Therefore, for F *not* to be divisible by 100, we must have $a < 2$ or $c < 2$.
We need factors that satisfy both conditions:
Combining these, we need:
Since $c \ge 2$ is required by the first condition, the second condition simplifies. The combined condition becomes ($a \ge 1$ and $c \ge 2$) AND ($a < 2$).
This simplifies further to $a = 1$ and $c \ge 2$.
Now, let's find the possible ranges for the exponents $a, b, c, d$ that meet all requirements:
The total number of factors satisfying the conditions is the product of the number of possibilities for each exponent:
Number of factors = (Possibilities for $a$) $\times$ (Possibilities for $b$) $\times$ (Possibilities for $c$) $\times$ (Possibilities for $d$)
Number of factors = $1 \times 4 \times 3 \times 3 = 36$.
There are 36 factors of $2^3 \times 3^3 \times 5^4 \times 7^2$ that are divisible by 50 but not by 100.
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