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Question

Let XYZ be a three-digit number, where (x + y + Z) is not a multiple of 3. Then (XYZ + YZX + ZXY) is not divisible by

The correct answer is

9

Correct Answer - Option 2 : 9 

Given:

XYZ is a three-digit number

Where (X + Y + Z) is not a multiple of 3

Concept used:

General form of a number XYZ = X × 100 + Y × 10 + Z

Calculation:

The general form of XYZ = 100X + 10Y + Z.

The general form of YZX = 100Y + 10Z + X

The general form of ZXY = 100Z + 10X + Y.

Using above, add the three numbers, we get ;

⇒ XYZ + YZX + ZXY = (100X + 10Y + Z) + (100Y + 10Z + X) + (100Z + 10X + Y)

⇒ XYZ + YZX + ZXY = 111X + 111Y + 111Z

⇒ XYZ + YZX + ZXY = 111(X + Y + Z).

Now, it is clear that 111 is the common factor.

So, XYZ + YZX + ZXY is divisible by 111 and it's factors

Factors of 111 are 3 and 37. That eliminate option 3 and 37

But it is given that (X + Y+ Z) is not multiple of 3

⇒ (XYZ + YZX + ZXY) is not divisible by 9.

⇒ (XYZ + YZX + ZXY) is not divisible by 9.

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Important Questions from Number System

  1. What is the value of 1 2 + 2 2 + 3 2 + ......21 2 ?

  2. Which sequence is correct to represent the hierarchical chain of number system?

    (Where N - Natural Numbers

    W - Whole Numbers

    Q - Rational Numbers

    Z - Integers)

  3. What must be added to 45680 to make it exactly divisible by 9?

  4. How many zeroes are there at the end of the following product? 

    1 x 5 x 10 x 15 x 20 x 25 x 30 x 35 x 40 x 45 x 50 x 55 x 60

  5. Let p, q, r and s be natural numbers such that p - 2016 = q + 2017 = r – 2018 = s + 2019 which one of the following is the largest natural number?

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