Let XYZ be a three-digit number, where (x + y + Z) is not a multiple of 3. Then (XYZ + YZX + ZXY) is not divisible by
9
Correct Answer - Option 2 : 9
Given:
XYZ is a three-digit number
Where (X + Y + Z) is not a multiple of 3
Concept used:
General form of a number XYZ = X × 100 + Y × 10 + Z
Calculation:
The general form of XYZ = 100X + 10Y + Z.
The general form of YZX = 100Y + 10Z + X
The general form of ZXY = 100Z + 10X + Y.
Using above, add the three numbers, we get ;
⇒ XYZ + YZX + ZXY = (100X + 10Y + Z) + (100Y + 10Z + X) + (100Z + 10X + Y)
⇒ XYZ + YZX + ZXY = 111X + 111Y + 111Z
⇒ XYZ + YZX + ZXY = 111(X + Y + Z).
Now, it is clear that 111 is the common factor.
So, XYZ + YZX + ZXY is divisible by 111 and it's factors
Factors of 111 are 3 and 37. That eliminate option 3 and 37
But it is given that (X + Y+ Z) is not multiple of 3
⇒ (XYZ + YZX + ZXY) is not divisible by 9.
⇒ (XYZ + YZX + ZXY) is not divisible by 9.
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