To find the number of divisors of 120, we first find its prime factorization.
120 can be broken down into its prime factors:
The prime factorization of 120 is $2^3 \times 3^1 \times 5^1$.
If the prime factorization of a number $N$ is $p_1^{a_1} \times p_2^{a_2} \times \dots \times p_k^{a_k}$, the total number of divisors is given by the product of one more than each exponent:
Number of Divisors = $(a_1+1)(a_2+1)\dots(a_k+1)$
For 120, the prime factorization is $2^3 \times 3^1 \times 5^1$. The exponents are 3, 1, and 1.
Therefore, the number of divisors of 120 is 16.
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