Let the three numbers be represented by $a$, $b$, and $c$. The question states that the sum of these three numbers is zero:
$a + b + c = 0$
We need to find the value of the sum of their cubes, which is $a^3 + b^3 + c^3$. There is a standard algebraic identity:
If $a + b + c = 0$, then $a^3 + b^3 + c^3 = 3abc$
This identity directly shows the relationship when the sum of three numbers is zero. The sum of the cubes ($a^3 + b^3 + c^3$) is equal to three times the product of the numbers ($3abc$).
Therefore, the correct option is the one that states 'three times the product of the three numbers'.
In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.
I. x2 – 26x + 165 = 0
II. y2 – 38y + 357 = 0
Factorize the following:
(x 2- 6xy + 9y 2) - 25
If P and Q are the points on the line Joining A(-2, 5) and B(3, 1) such that
AP = PQ = QB, then the mid point of PQ is
If a number and its reciprocal added it becomes 6, then what will be sum of its square and square of its reciprocal?
If 3x + 2y = 15, and xy = 6. Find the value of (3x3/2) + (4y3/9).