We are given a total of 1200 apples to distribute among a group of boys.
Let the number of boys in the group be represented by the variable $B$.
According to the problem, each boy received thrice the number of boys in the group. Therefore, the number of apples each boy received is $3 \times B$.
The total number of apples distributed is the product of the number of boys and the number of apples each boy received.
Total Apples = (Number of Boys) $\times$ (Apples per Boy)
We can write this as an equation:
$ B \times (3 \times B) = 1200 $Simplify the equation:
$ 3 \times B^2 = 1200 $To find $B^2$, divide both sides by 3:
$ B^2 = \frac{1200}{3} $ $ B^2 = 400 $Now, find the value of $B$ by taking the square root of both sides:
$ B = \sqrt{400} $ $ B = 20 $The number of boys in the group is 20.
This matches the given total number of apples.
In the given question, two equations numbered l and II are given. Solve both the equations and mark the appropriate answer.
I. x2 – 26x + 165 = 0
II. y2 – 38y + 357 = 0
Factorize the following:
(x 2- 6xy + 9y 2) - 25
If P and Q are the points on the line Joining A(-2, 5) and B(3, 1) such that
AP = PQ = QB, then the mid point of PQ is
If a number and its reciprocal added it becomes 6, then what will be sum of its square and square of its reciprocal?
If 3x + 2y = 15, and xy = 6. Find the value of (3x3/2) + (4y3/9).