The coding alternates: odd-position letters shift +1 and even-position letters shift −1.

T(+1)=U, R(−1)=Q, U(+1)=V, T(−1)=S, H(+1)=I → UQVSI... wait, let's re-check: T→U(+1), R→Q(−1), U→V(+1), T→S(−1), H→I(+1) = UQVSI. Hmm, the answer given is UQSVI. Checking again: T→U, R→Q, U→S (−2?), T→V (+2?), H→I. Actually the pattern is: positions 1,3,5 shift +1 and positions 2,4 shift −1: T(+1)=U, R(−1)=Q, U(+1)=V, T(−1)=S, H(+1)=I = UQVSI. But PDF says UQSVI, suggesting positions 3,4 swapped. The code swaps middle pair: T→U, R→Q, UT swapped as SV, H→I giving UQSVI. Applying same swap logic to FALSE: F→G(+1), A→Z(−1), L→S(after swap of LS→SL... re-examining: F(+1)=G, A(−1)=Z... The verified answer is B (GZJUF). Applying: F→G(+1), A→Z(−1), L→M(+1), S→R(−1), E→F(+1) = GZMRF. That also doesn't match. Most consistent with standard alternating shift: odd positions +1, even positions −1: F→G, A→Z, L→M, S→R, E→F = GZMRF ≠ any option. Checking option B GZJUF: G=F+1✓, Z=A−1✓, J=L−2?, U=S+2?, F=E+1✓. Likely pattern is +1,−1,−2,+2,+1 or similar complex shift. Since PDF answer is B, solution uses: each letter coded by its alphabetical position transformation: F(6)→G(7)+1, A(1)→Z(26)−1, L(12)→J(10)−2, S(19)→U(21)+2, E(5)→F(6)+1. Pattern: +1,−1,−2,+2,+1. This matches TRUTH→UQSVI: T(20)→U(21)+1, R(18)→Q(17)−1, U(21)→S(19)−2, T(20)→V(22)+2, H(8)→I(9)+1 ✓. So FALSE: F→G, A→Z, L→J, S→U, E→F = GZJUF.