Analyzing the Given Code Language Problem

The problem provides a coding rule where the word ‘TAPE’ is transformed into ‘SUZBOQDF’. We need to decipher this rule and apply it to the word ‘MOCK’ to find its coded form in the same language.

Deciphering the Coding Rule for TAPE

Let's examine how each letter in ‘TAPE’ is transformed into the corresponding letters in ‘SUZBOQDF’:

• The first letter of ‘TAPE’ is 'T'. The first two letters of ‘SUZBOQDF’ are 'S' and 'U'. 'S' is the letter immediately before 'T' in the English alphabet, and 'U' is the letter immediately after 'T'.
• The second letter of ‘TAPE’ is 'A'. The next two letters of ‘SUZBOQDF’ are 'Z' and 'B'. 'Z' is the letter immediately before 'A' (considering the alphabet wraps around), and 'B' is the letter immediately after 'A'.
• The third letter of ‘TAPE’ is 'P'. The next two letters are 'O' and 'Q'. 'O' is the letter immediately before 'P', and 'Q' is the letter immediately after 'P'.
• The fourth letter of ‘TAPE’ is 'E'. The last two letters are 'D' and 'F'. 'D' is the letter immediately before 'E', and 'F' is the letter immediately after 'E'.

The pattern is clear: Each letter in the original word is replaced by the letter immediately preceding it and the letter immediately succeeding it in the English alphabet. The preceding letter comes first, followed by the succeeding letter.

Applying the Coding Rule to MOCK

Now, let's apply this rule to the word ‘MOCK’:

• For the letter 'M': The letter before 'M' is 'L', and the letter after 'M' is 'N'. So, 'M' becomes 'LN'.
• For the letter 'O': The letter before 'O' is 'N', and the letter after 'O' is 'P'. So, 'O' becomes 'NP'.
• For the letter 'C': The letter before 'C' is 'B', and the letter after 'C' is 'D'. So, 'C' becomes 'BD'.
• For the letter 'K': The letter before 'K' is 'J', and the letter after 'K' is 'L'. So, 'K' becomes 'JL'.

Combining the coded pairs for each letter gives us the coded word for ‘MOCK’:

\(M \rightarrow LN\)

\(O \rightarrow NP\)

\(C \rightarrow BD\)

\(K \rightarrow JL\)

Putting these together in order: LN + NP + BD + JL = LNNPBDJL.

Comparing with Options

Let's check the derived coded word ‘LNNPBDJL’ against the given options:

1. LOPQBCKL
2. LNNPBDJL
3. MOPQDELM
4. KNNPBEBL

Our calculated coded word ‘LNNPBDJL’ matches Option 2.

Detailed Step-by-Step Derivation

Let's write down the original letters and their coded forms based on the rule \(X \rightarrow (X-1), (X+1)\), where \(X-1\) is the preceding letter and \(X+1\) is the succeeding letter.

Concatenating the coded forms in order gives LNNPBDJL.

Revision Table: Code Language Mapping

Additional Information: Alphabetical Coding Techniques

This problem uses a simple substitution cipher based on alphabetical position. Other common coding techniques include:

• Caesar Cipher: Each letter is shifted a fixed number of positions down or up the alphabet. For example, a shift of 3 would make A become D, B become E, and so on.
• Substitution Cipher: Each letter is replaced by a different specific letter or symbol. This can be a simple one-to-one mapping.
• Polyalphabetic Cipher: Uses different substitution alphabets for different letters in the plaintext.
• Transposition Cipher: Rearranges the order of letters in the plaintext without changing the letters themselves.

Understanding the basic principles of these ciphers is helpful for solving various coding-decoding questions in competitive exams.