If a trapezium has bases of lengths 8 cm and 12 cm, and height of 5 cm, what is its area?
50 cm²
Area of a trapezium: \(\tfrac12\times(a+b)\times h\), with bases 8 cm and 12 cm and height 5 cm.
Area: \(\tfrac12\times(8+12)\times5 = \tfrac12\times20\times5 = 50\) cm2.
Hence, the area of the trapezium is 50 cm2.
Calculate the area of the triangle whose sides are 8 cm, 9 cm and 13 cm. (Rounded up to two decimal places)