Areatriangle = $\frac{\sqrt{3}}{4} s^2$
For a triangle with side $x$, the area is:Areatriangle = $\frac{\sqrt{3}}{4} x^2$
Areasquare = $s^2$
For a square with side $x$, the area is:Areasquare = $x^2$
Ratio = Areatriangle : Areasquare
Substitute the formulas:Ratio = $\left( \frac{\sqrt{3}}{4} x^2 \right) : (x^2)$
To simplify the ratio, divide both sides by $x^2$ (assuming $x \neq 0$):Ratio = $\frac{\sqrt{3}}{4} : 1$
Multiply both sides by 4 to eliminate the fraction:Ratio = $\sqrt{3} : 4$
The final ratio is $\sqrt{3} : 4$.Calculate the area of the triangle whose sides are 8 cm, 9 cm and 13 cm. (Rounded up to two decimal places)