Calculate the area of the triangle whose sides are 8 cm, 9 cm and 13 cm. (Rounded up to two decimal places)
This problem asks us to find the area of a triangle given the lengths of its three sides: 8 cm, 9 cm, and 13 cm. We can solve this using Heron's formula, which is a useful method when all three side lengths are known.
Heron's formula allows us to calculate the area of a triangle when we know the lengths of all three sides. Let the sides of the triangle be $a$, $b$, and $c$.
First, we need to calculate the semi-perimeter ($s$) of the triangle, which is half of the perimeter. The formula for the semi-perimeter is:
$s = \frac{a+b+c}{2}$
Once we have the semi-perimeter, we can use Heron's formula for the area (A):
Area $= \sqrt{s(s-a)(s-b)(s-c)}$
Let's apply Heron's formula to the given triangle with sides $a=8$ cm, $b=9$ cm, and $c=13$ cm.
Using the formula $s = \frac{a+b+c}{2}$:
$s = \frac{8 \text{ cm} + 9 \text{ cm} + 13 \text{ cm}}{2}$
$s = \frac{30 \text{ cm}}{2}$
$s = 15 \text{ cm}$
Now, substitute the value of $s$ and the side lengths into Heron's formula:
Area $= \sqrt{s(s-a)(s-b)(s-c)}$
Area $= \sqrt{15(15-8)(15-9)(15-13)}$
Area $= \sqrt{15(7)(6)(2)}$
Let's multiply the numbers inside the square root:
Area $= \sqrt{15 \times 7 \times 6 \times 2}$
Area $= \sqrt{105 \times 12}$
Area $= \sqrt{1260}$
Now, we calculate the square root of 1260 and round it to two decimal places as requested:
Area $\approx 35.50 \text{ cm}^2$
The area of the triangle with sides 8 cm, 9 cm, and 13 cm is approximately 35.50 cm².