The problem provides the dimensions of a rectangular field: length ($l$) = 169 m and width ($w$) = 154 m. The first step is to calculate the area of this rectangular field.
The formula for the area of a rectangle is:
$$ A_{\text{rectangle}} = \text{length} \times \text{width} $$Substituting the given values:
$$ A_{\text{rectangle}} = 169 \, \text{m} \times 154 \, \text{m} $$ $$ A_{\text{rectangle}} = 26026 \, \text{m}^2 $$So, the area of the rectangular field is 26026 square meters.
The problem states that the area of the rectangular field is equal to the area of a circular field. We know the area of the rectangle is $26026 \, \text{m}^2$. The formula for the area of a circle is:
$$ A_{\text{circle}} = \pi r^2 $$where $r$ is the radius of the circular field and $\pi = \frac{22}{7}$.
Since the areas are equal:
$$ A_{\text{circle}} = A_{\text{rectangle}} $$ $$ \pi r^2 = 26026 $$Now, we substitute the value of $\pi$ and solve for $r$:
$$ \frac{22}{7} r^2 = 26026 $$To find $r^2$, we rearrange the equation:
$$ r^2 = 26026 \times \frac{7}{22} $$Performing the division:
$$ r^2 = 1183 \times 7 $$ $$ r^2 = 8281 $$Now, we find the radius $r$ by taking the square root of $r^2$:
$$ r = \sqrt{8281} \, \text{m} $$ $$ r = 91 \, \text{m} $$The radius of the circular field is 91 meters.
The final step is to calculate the circumference of the circular field using its radius. The formula for the circumference of a circle is:
$$ C_{\text{circle}} = 2 \pi r $$Substitute the values of $\pi$ and $r$:
$$ C_{\text{circle}} = 2 \times \frac{22}{7} \times 91 \, \text{m} $$Simplify the calculation:
$$ C_{\text{circle}} = 2 \times 22 \times \frac{91}{7} \, \text{m} $$ $$ C_{\text{circle}} = 44 \times 13 \, \text{m} $$ $$ C_{\text{circle}} = 572 \, \text{m} $$Therefore, the circumference of the circular field is 572 meters.
Calculate the area of the triangle whose sides are 8 cm, 9 cm and 13 cm. (Rounded up to two decimal places)