The problem asks for the area of an equilateral triangle with a side length of 10 m.
The area ($A$) of an equilateral triangle with side length ($s$) is given by the formula:
$ A = \frac{\sqrt{3}}{4} s^2 $
Given the side length $s = 10$ m, substitute this value into the formula:
Using the approximate value of $ \sqrt{3} \approx 1.732 $:
Now, compare the calculated area ($ \approx 43.30 \text{ m}^2 $) with the given options:
The calculated area, $43.30 \text{ m}^2$, is closest to Option 3, $43.25 \text{ m}^2$.
Calculate the area of the triangle whose sides are 8 cm, 9 cm and 13 cm. (Rounded up to two decimal places)